Recent content by CSG18

Thank you, I'm glad that's resolved.

I just meant that the moles of iodine that I had initially calculated (0.112 mol) applied to I2 (a molecule of iodine), however I was asking instead of finding I2, the goal was to find just the number of moles of I. Does that make sense?

Thank you Mr. Borek. I just could not figure out where I had gone wrong.

Oh! Because iodine is diatomic, so there are 2 iodine atoms for every 0.112mols, for 1 iodine atom there are 0.056 mols, so that means the molar ratio is 4! So there are 4 double bonds?! The answer 0.056 is approximately equal to 0.0559! Thankyou thankyou soo much! So you always have...

8...? Is that the number you are talking about? Because I had already calculated 8, but the answer in my book says 0.0559 mols...?

Are you serious?! 3:2

I have tried everything I know. With respect, if I knew how to do these questions then I wouldn't be asking. So if I could see how someone else worked it out, I will be able to see how its done, so I can apply it to similar questions. Sorry for the trouble, I'm quite desperate.

Thats all the information that was given, and Its just a revision question - not homework.

The hints were wrong though. Its ok though, I understand it now.

Hi, I understand that the iodine number is the number of moles of iodine reacting with one mole of fat/oil which indicates the number of double bonds present in the fat/oil molecule. However I am having trouble calculating them. Can someone show me how to solve the following question...

Insert Quote Hi, I would be very grateful if anyone could show me how to answer the following question: The value of x in Fe(NH4)2(SO4)2. xH2 O can be found by determining the amount in moles of sulfate in the compound. A 0.982g sample was dissolved in water and excess BaCl2 (aq) was added...