Recent content by cuppy

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    Calculating Magnetic Field at Point P

    1. Homework Statement What is the magnitude of the magnetic field at point P if a=R and b=2R (see attached image) 2. Homework Equations Ampere's Law where integral of B ds over a closed surface = μ0I where μ0= 4πx10-7 3. The Attempt at a Solution I used the formula and found...
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    Help are any of these even correct?

    I've done some background research but can't find a definite answer to this question. At first i suspected the answer to be A but everyone seems to have their own thoughts about it: The reason the north pole of a bar magnet (which is free to rotate) points north is because: a. the south...
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    Charges on spherical conductors

    A charge is placed on a speherical conductor of radius r1. this sphere is then connected to a distant sphere of radius r2 (not equal to r1) by a conducting wire. after the charges on the spheres are in equilibrium... is it reasonable to say that both spheres are at the same potential...
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    Potential difference and a proton

    ok i will definitely keep that in mind for next time.
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    Where Does the Electric Potential Equal Zero Along the X-axis?

    Two charges lie on the x-axis +2q at the origin and -3q at x=5m. The point on the x-axis where the electric potential has a zero value is?? relevant equations- V=kq/r my solution- since electric potential is a scalar quantity i reasoned that when you add the potentials of both charges...
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    Kinetic Energy of Point Charges

    Identical 8-μc point charges are positioned on the x-axis at x=+/-1.0m and released from rest simultaneously. What is the kinetic energy of either of the charges after it has moved 2.0m? some relevant formulas are: E=kq/r^2 V=-Ed V=U/q my attempt at the question: i started by finding...
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    Potential difference and a proton

    hey THANKS :approve: i can't believe i didn't see that before! taking that approach, i used delta V= delta U/q after finding delta U from delta KE = - delta U so 1/2mv^2 final - 1/2mv^2 initial equalled 3.2565x10^-18, so change in potential energy was -3.2565x10^-18. dividing that by the...
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    Potential difference and a proton

    Homework Statement a proton (mass=1.67x10^-27kg, charge 1.6x10^-19C) moves from point A to point B under the influence of an electrostatic force only. at point A the proton moves with a speed of 50km/s and at point b it moves with a speed on 80km/s. determine the potential difference vb-va...
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