Just to add on for method 2:
For flowing water, you can incorporate the water flow rate (in mL per second) (1g = 1mL roughly), to help convert the energy to power
G'Day
For the efficiency you would use output energy / input energy (not the other way around).
To be honest I don't really get what you mean by "The energy source should be a standard 150W light bulb connected to the 230V mains. "
But I'll help where I can.
For method one, you would use...
Surely after a number of years you would have memorised the electromagnetic spectrum in a similar method to how you memorised the alphabet?
I think it just "makes sense" by considering the applications of the different frequency ranges (low frequency like radio/tv , then microwaves/radar...
@tmaon: Have you had a look at the 'Introductory Physics Tutorials' forum link above ?
Hopefully there should be a link to Walter Lewin's physics courses (there is emag and some optics topics) taught at MIT, my favourites.
Person in question is Ghim Wei Ho ( http://www.esp.nus.edu.sg/Research/Biography_Dr%20Ho.htm ) at NUS.
Not sure how it is in Singapore but in Australia it's possible to do a Bach. of Engineering and a Masters of Biomedical Engineering (coursework) in one five year stretch and graduate with...
Appreciate the responses guys.
The layer is about 2microns thick, supported by glass.
I don't think anything that melts the material would be suitable
Mechanically compressing sounds interesting. I will look into that, but another problem is that the Al is about 1mm wide (by an arbitrary...
Hi guys,
Not sure whether this belongs in elec or mats/chem so I thought I'd put it here.
Basically I am trying to extract current from a thin aluminium layer.
Due to the Al-Oxide layer, simply soldering an external lead isn't working.
I'm able to etch away (some?) of the oxide layer...
I think you have a good understanding of the dc series resistive circuits, I've attached an (also crappy) picture to help a bit.
That symbol the the left/bottom indicates where I've (arbitrarily) selecting my 'reference' voltage of 0 volts to be.
If you provide an alternate path for the...
It's basically a conservation law.
If a wire 'forks' into 2, the current going into this point is equal to the sum of the 2 currents leaving. (cars entering an intersection = cars exiting an intersection, regardless which street they take)
"If I was to put a resistor on one end of the...
There's a lot of things we would like to change as with time we find things are different to what we first thought.
Have a look at the definition for the word 'atom' (greek root) :smile:
http://www.arwu.org/ARWU-FIELD2007/ENG.htm
"published by the Institute of Higher Education, Shanghai Jiao Tong University (IHE-SJTU). It has been done independently by the ranking team in IHE-SJTU for their academic interests without any external financial support. "
Disclaimer...
Ok firstly, in the series circuit you describe we would have
P=IV=7A*7V = 49Watts of power being dissipated
If you double the resistance, and the voltage remains at 7V, then sure, there would be 3.5A of current.
This of course means that less power is being dissipated,
P=IV=24.5Watts...
Is this the Horowitz book? I think it's a great introductory text.
I think the definition given in the book is quite ok, and with the help of a diagram I would be happy if I was learning voltage concepts with that principle.
(Voltage as a 'height' or as an analog to gravitation potential)...
Ian, do you go the the University of New South Wales (Sydney) by any chance ?
That course description for APV looks incredibly familiar, but 'junior year' is not common terminology in Australia.
Thought I'd ask to make sure..