Recent content by curiousatlarg

Thanks. I was referring to both the electric and the magnetic fields. What you gave me so far is what I was looking for. I will work with it some.

Hello all! I am trying to understand ER on a more intuitive level. I can see the relationship between energy and frequency. The relationship between amplitude and photon number is less clear. So far I have E = hf. I understand that the intensity of light is a function of the number of...

That is useful. I am still trying to visualize the E an H fields. I am working on reading the "millions of words".

I am rusty at this and my math is slow motion hack work. From what I read, N is the number of electrons intercepting the x axis. The angle is the angle of incidence or the angle of the cone of light emitted. I know it's an old thread, but if you have worked it, I would like to see it. That...

The refractive index (n) directly relates to the speed of light in the glass. n = c (speed of light in a vacuum) / v (speed of light in a medium).

500THz correspnds to visible orange light in air. The antenna should be 600 nm. No idea if it would work. Guess you would need a bunch of them to see them. No idea about the electons in the wire. Maybe not using metal conductors would be the answer. I wonder how such a nano antenna could...

OK, as for the waves, I refer to a representative graph of light waves. However, are not high frequencies also high energy ( E = hf)? As for the path, couldn't the flux be measured anywhere on the path? If so, then, for practical purposes, the photon follows a "path", although, having it...

So, if I am correct, the light will be converted to heat in the wire, unless it is a nano antenna, or if the light is the of higher frequency than required for the threshold of the metal. Thank you for your replies.

Ah, yes, the origional question was why light does not transfer signals to wires. I was supposing that a nano antenna made of wire could work somehow, and also wondering what happens when light strikes any metal wire.

Thanks!

Huh? No it wouldn't. The smaller the wavelength, the greater the energy of the photon. Overall flux can be raised by increasing the intensity of the photon stream, or by increasing the energy of the photons. A UV photon of say 200 nm has a greater energy than an IR photon, and much more...

I think I should make a table of wavelengths and predicted responses.

OK, that makes sense. Next, what happens to the EM radiation? In some cases, electrons are ejected (for wavelengths below 293 nm), other cases, photons are emitted. In others a current is produced (if the metal object is the right length. For example, would a nano antenna generate electricity...

Photons striking elecrons in metal will add energy and excite the electron. If the energy of the photon is greater than the threshold energy for that metal, the electron will be ejected. However, if the photon is not, the electron will return to it's origional orbit, but in the process...

My understanding is that all of the above are EM, and all are photons, and the photons travel at the speed of light. The energy of a photon is inversely propotional to the wavelngth. The waves per meter per second for example would show the energy required to make that many ocillations per...