Recent content by Dalip Saini

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    Work Done on 500N Barbell 0.5m Above Floor

    Its the distance of the barbell above the ground. So is that vector pointing down and the force is pointing up? But still cos(180) is still -1 not 0
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    Work Done on 500N Barbell 0.5m Above Floor

    Homework Statement You hold a 500N barbell 0.5m above a level floor for 100s . During this time, the amount of work you do on the barbell is A 1000J B 0J C 500J D 50000J Homework Equations W = Fdcos(phi) The Attempt at a Solution F= 500 N d = 0.5 m Since the...
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    Terminal Velocity of Cube: 1.6 m/s

    Homework Statement cube has a drag coefficient of 0.90. What would the terminal velocity of this cube be, 1.0 cm on a side in air (ρ = 1.2 kg/m3)? Take the density of this cube to be 1.6 x 103 kg/m3. A 68 m/s B 1.6 m/s C 5.6 m/s D 20 m/s E 360 m/s Correct answer...
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    Find the Coefficient of Kinetic Friction for Crate Movement

    Homework Statement A crate on a rough horizontal floor is being moved horizontally by a force applied at a 16 degree angle above the horizontal. This is the smallest force that will move the crate at constant speed. What is the coefficient of kinetic friction? A : .11B : .27 C ...
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    Frictional Force vs normal force

    Homework Statement A 10 N horizontal force is applied to a 50 N block initially at rest on a rough horizontal surface. If the coefficient of static friction is 0.5 and the coefficient of kinetic friction is 0.4, then the frictional force on the block is A 10 N B 20 N C 0 N D...
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    Wavelength of traveling wave on string (one end clamped and one end free)

    1. Homework Statement A 30-cm long string, with one end clamped and the other free to move transversely, is vibrating in its second harmonic. The wavelength of the constituent traveling waves is A -- 10 cm B -- 40 cm C -- 120 cm D -- 30 cm E -- 60 cm Homework Equations for second...
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    Classifying standing waves and their frequencies

    Homework Statement 40-cm long string, with one end clamped and the other free to move transversely, is vibrating in its fundamental standing wave mode. If the wave speed is 320 cm/s, the frequency is[/B] A 16 Hz B 8 Hz C 32 Hz D 2 Hz E 4 Hz Homework...
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    Simple Harmonic Motion and phase constant

    since the initial velocity is zero, would u take the derivative of the function to get v=-wxmsin(wt+φ). Then plug in the values to get 0 = -240(0.035)sin[(240)(0)+φ). Then solve for φ and get zero. According to the assignment the correct answer is zero. Is this the correct way to solve it?
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    Finding mechanical energy of simple harmonic oscilator

    Actually I just plugged in the values again and I got the answer. Sorry about that
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    Finding mechanical energy of simple harmonic oscilator

    k=240 N/m x=0.035m m=0.045 v = 2.5 m/s
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    Finding mechanical energy of simple harmonic oscilator

    Homework Statement A simple harmonic oscillator consists of a block of mass 45 g attached to a spring of spring constant 240 N/m, oscillating on a frictionless surface. If the block is displaced 3.5 cm from its equilibrium position and released with an initial velocity of 2.5 m/s, what is its...
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    Simple Harmonic Motion and phase constant

    Im really stuck on how to solve this problem. I know that the Xm is 0.035m. I also know that the w can be solved for using sqroot(k/m). But I'm stuck now on how to use this information to solve for the answer
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