Finding mechanical energy of simple harmonic oscilator

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Homework Help Overview

The discussion revolves around calculating the total mechanical energy of a simple harmonic oscillator, specifically a block attached to a spring. The parameters include the mass of the block, the spring constant, the displacement from equilibrium, and the initial velocity.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the energy formula for a simple harmonic oscillator and share their calculations. There is a question about the values used in the formula and the resulting total energy.

Discussion Status

The discussion has progressed with one participant initially expressing confusion over their calculation, but later confirming that they arrived at the correct answer after re-evaluating their inputs. There is an acknowledgment of the potential for error in the calculation process.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the extent of guidance provided. There is an emphasis on ensuring the correct application of the formula and the values used in the calculations.

Dalip Saini
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Homework Statement



A simple harmonic oscillator consists of a block of mass 45 g attached to a spring of spring constant 240 N/m, oscillating on a frictionless surface. If the block is displaced 3.5 cm from its equilibrium position and released with an initial velocity of 2.5 m/s, what is its total energy?
  • A

    0.15 J
  • B

    The total energy varies during each cycle of oscillation.
  • C

    0.20 J
  • D

    0.29 J
  • E

    0.14 J

Homework Equations


E = 0.5kx^2+0.5mv^2

The Attempt at a Solution


I plugged in the values into the formula and I got 0.14J but the answer is 0.29J
 
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Dalip Saini said:

Homework Statement



A simple harmonic oscillator consists of a block of mass 45 g attached to a spring of spring constant 240 N/m, oscillating on a frictionless surface. If the block is displaced 3.5 cm from its equilibrium position and released with an initial velocity of 2.5 m/s, what is its total energy?
  • A

    0.15 J
  • B

    The total energy varies during each cycle of oscillation.
  • C

    0.20 J
  • D

    0.29 J
  • E

    0.14 J

Homework Equations


E = 0.5kx^2+0.5mv^2

The Attempt at a Solution


I plugged in the values into the formula and I got 0.14J but the answer is 0.29J
What values did you plug into the formula?
 
k=240 N/m
x=0.035m
m=0.045
v = 2.5 m/s
 
Actually I just plugged in the values again and I got the answer. Sorry about that
 

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