Recent content by daNAV1GATOR

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    Solubility of a gas in water Kinetic Molecular Theory

    How about this: According to the kinetic molecular theory, increasing the temperature of water increases the kinetic energy of gas (and water) molecules, which then causes them to move faster. I learned in Physics that this is how evaporation works: Fast moving water molecules collide with...
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    Solubility of a gas in water Kinetic Molecular Theory

    Homework Statement The solubility of a gas in water decreases as temperature increases, and increases as temperature decreases. Using the kinetic molecular theory, explain why this is so. I would like an opinion please on my answer below. Is it a sufficient explanation? THANKS! :smile...
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    [Multiple Choice] wavelength of an object. de Broglie wavelength

    Okay... the answer does seem to be (B), Electron orbiting a nucleus. Quick moving bee = 2 x 10^{-31} m (0.0005 kg, 6.7 m/s) Electron = 10^{-10} m Elephant = 10^{-37} m (3000 kg, 2 m/s) Earth = 10^{-39} m (6 x 10^{24} kg, 30,000 m/s) T H A N K S . G U Y S ! ! ! i'M nOw dOnE...
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    Radioactive decay. Is energy released? OPINION PLEASE

    [SOLVED] Radioactive decay. Is energy released? OPINION PLEASE! This is my last question in my last Physics exam! YES! I'M ALMOST DONE! :smile: I would just like your opinion on this question... My answer is Yes... But sometimes I think it should be NO because of the question's option for a No...
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    Help with Energy unit Joules EASY

    So that's understood? I'll then just add... E = mc^{2} . .= (3.6 x 10^{9} kg)(3 x 10^{8} m/s)^{2} . .= (3.6 x 10^{9} kg)(9 x 10^{16} m^{2}/s^{2}) . .= 32.4 x 10^{25} \frac{kg \cdot m^2}{s^2} . .= 32.4 x 10^{25} Joules Simple as that? Yipee! :biggrin: Are my calculations correct...
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    Help with Energy unit Joules EASY

    Hmmm... well Joule is the unit of work. N*m Newton x meter
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    Help with Energy unit Joules EASY

    [SOLVED] Help with Energy unit ... Joules... EASY! Homework Statement The sun burns up 3.6 x 10^{9} kg of matter each second. Using the formula E = mc^{2}, determine how much energy the sun releases each second. [Speed of light: 3 x 10^{8} m/s] Homework Equations E = mc^{2}...
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    [Multiple Choice] wavelength of an object. de Broglie wavelength

    Ahhh... okay. E for EXPONENT. duh! so it's 10^{8}
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    [Multiple Choice] wavelength of an object. de Broglie wavelength

    Do you think I should? It's just supposed to be a simple problem... 'What would I expect'... But since I don't know what to expect... oh well. Fine, I'll put some figures in. :frown:
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    [Multiple Choice] wavelength of an object. de Broglie wavelength

    Can you translate please? hehehe :confused::smile: I don't understand "3E8" ... "E-27"...
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    [Multiple Choice] wavelength of an object. de Broglie wavelength

    Good point... should I just make estimates? The question doesn't give any figures.
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    [Multiple Choice] wavelength of an object. de Broglie wavelength

    [SOLVED] [Multiple Choice] ...wavelength of an object. de Broglie wavelength 1. THE PROBLEM STATEMENT MULTIPLE CHOICE Which of the following would you expect to have the largest wavelength associated with it? (A) a quick-moving bee (B) an electron orbiting a nucleus (C) a slowly lumbering...
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    Radioactivity - Why no reading on Geiger counter?

    Thank you, malawi_glenn. What's "OP" stand for? I did attemt a solution in my first post. I am very grateful to _Mayday_ and astrorob for making me realize that the magnet has an effect on radioactivity. It made me review the chapter in my textbook again.
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    Radioactivity - Why no reading on Geiger counter?

    Okay... I confirmed what you said, astrorob... and so how about this as my answer: Again, the first question is, if the Geiger counter is not registering any radioactivity, what kinds of particles is the radioactive substance emitting? Answer: The substance may be emitting one, two, or all...
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    Radioactivity - Why no reading on Geiger counter?

    Magnet illustration = please look at, _Mayday_ Here's the illustration in my textbook. Please click on the image: Magnet.jpg I'm basically imagining now that the Geiger counter is above the magnet. It should then be getting gamma radiation... But since the question is saying it's not, then...
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