Thanks Doc Al
So the net amount that got through both polarizers was .369, but it says that .146 got through.
The amount that went throught the first would just be (cos38.8)^2 = .607.
I still don't know how this would help me to get the answer...
Through 1st polarizer => .607
Through...
Two polarizers are oriented at 38.8o to each other and plane-polarized light is incident on them. If only 14.6 percent of the light gets through both of them, what was the initial polarization direction of the incident light?
Ok, I'm not exactly sure what this problem is asking for, do they...
Cyclovenom
I couldn't go to sleep before trying it again, haha.
But I got the first one correct, finally. :biggrin:
I ended up doing this E = kQ/((2/L^2)*cos45+(1/hyp^2))
So as the final answer I got 30384.3 N/C!
Still confused like crazy about the second question though... :confused:
Cyclovenom, yes I am familiar with unit vectors.
Wow, I was oversimplifying the problem. I feel kinda dumb for not thinking straight.
I will work on the problem tomorrow morning.
thank you for the great help once again!
ok, so I got the hypotnuse of the square to be 1.78191m.
After that I used the equation given above.
E=(9e9)*2.80e-6/1.78191^2
=7936.5 N/C
I muliplied that by three to get 23809.5 N/C, and that is not the correct answer either. I tried the problem again, but I used the side of the...
Stuck on two electric field questions...
Hi guys,
I have these two questions which I am unable to answer.
This is the first one:
Calculate the magnitude of the electric field at one corner of a square 1.26 m on a side if the other three corners are occupied by 2.80×10-6 C charges ...