What a know/think!
number 1??
I THINK.. it is
we know F=KX & W=MG
since F=W, KX=MG
so K*d=2kg*G also K*(d+2.5cm)=2.253kg*G
so K=(2kg*G)/d also K=(2.253kg*G)/(d+2.5cm)
then (2kg*G)/d = (2.253kg*G)/(d+2.5cm)
we solve for d: (d+2.5cm)/d= (2.253kg*G)/(2kg*G)
G...
A 2 kg block hangs from a spring. A 253g body hung below the block stretches it a further 2.5cm. What's the spring constant? Use g=9.8N/kg. Calculate the value to 1 decimal place and use N/m as your unit.
AND
A 1.8kg block hangs from a spring. A 221g body hung below the block...