Hi Vela, with the correction I got (M^2 -m^2)/2 = p^2 + p(p^2+m^2)^(1/2), with E = (p^2+m^2)^(1/2), and c = 1, which is kind of nasty (for me at least). So is four- momentum always the quickest way or just depends on the problem? Thanks
1. A particle of mass M decays from rest into two particles. One particle has mass m and the other particle is massless. The momentum of the massless particle is...
2. Ei = Ef, Pi= Pf
3. This is a GRE practice problem. I can solve this problem using the old method as listed in the step 2, but I...
Homework Statement
1) If one object is accelerating, there must be another object that is accelerating (T/F/N)
2) A stationary object can exert a kinetic force. (T/F/N)
Homework Equations
2) F=ma
The Attempt at a Solution
1) My answer is false for this one because if the object...