Recent content by dave84

So \eta = \frac{|A|}{Q_{in}} =\frac{|Q_{12}+Q_{34}|}{Q_{41} + Q_{12}} , where A is total work done and Q is the input heat. The final result is simplified with \kappa. Q_{in} = Q_{41} + Q_{12} Q_{out} = Q_{23} + Q_{34} = Q_{in} - A Q_{out} is the amount of heat that is released from the heat...

Homework Statement We have a Stirling heat engine. I'm calculating the efficiency \eta. Homework Equations Q_{12} = \frac{m R T_2}{M} \ln(\frac{V_2}{V_1}) > 0 Q_{23} = m c_v (T_1 - T_2) < 0 Q_{34} = \frac{m R T_1}{M} \ln(\frac{V_1}{V_2}) < 0 Q_{41} = m c_v (T_2 - T_1) > 0 \kappa =...

But there's nothing that could exchange heat with steam, it says that the piston and the interior doesn't conduct heat. Weird.

Homework Statement We have a horizontal cylinder with an ideal piston, both are made from a heat nonconductive material. There is 10 liters of steam at 3 bars and 200 degrees Celsius in the cylinder. The cylinder is surrounded with atmosfere with pressure of 1 bar and temperature at 20 degrees...