Recent content by DavisonH

The boiling point of water is 100 C, but the water measured in the lab as at 98 C. The left side is the metal, the right the water.

Thanks! The initial temperature of the boiling water is 98 C. Then I think it would go like this (86.79) C (100 C - 29.5C) = (100g) (1 cal/g-C)(5.3C) (86.79) (70.5C) C = 530 6118.7 C = 530 C = 0.0866 cal/g-C

Homework Statement Finding the specific heat capacity of an unknown metal. A cylinder was placed into boiling water, originally at 24.2 C. The heat transferred from the metal, and the water then was 29.5 C. Original Temperature-24.2 C Temperature after the metal has been placed into the...