Recent content by dawozel

Homework Statement Interstellar Spaceship An interstellar spaceship with initial mass Mo is at rest at the edge of a small, spherical nebula (gas cloud). At t= 0, the engines begin to fire, ejecting gas out the back at constant speed u relative to the rocket. The mass of the rocket decreases...

Thanks for your help sir!

Hmmmm i may be forgetting to multiply the F' (x) by G(x) and vice versa Is the derivative closer to A((((aexp((-1/2)ax^2) + (-a^2x^2exp((-1/2)ax^2))(5-2ax^2) + (4ax)( \alpha x \exp(-\frac{1}{2}\alpha x^2))

so my second derivative should be A(((aexp((-1/2)ax^2) + (-a^2x^2exp((-1/2)ax^2)) +(4ax)) is this right or am i still missing a product rule?

So my first derivative was simplified to \frac{d}{dx}\psi_2(x)=A\left[4\alpha x e^{-\frac{1}{2}\alpha x^2} - (2\alpha x^2 - 1)\alpha x e^{-\frac{1}{2}\alpha x^2}\right] and if i factor out the \alpha x \exp(-\frac{1}{2}\alpha x^2) i get that \frac{d}{dx}\psi_2(x) = A(\alpha x...

yes that's my first derivative

My bad this is the second derivative A((4a)(exp(( - ax^2 ) / 2)) + (4ax) * ( - ax * exp(( - ax^2) /2)) + (4ax) * ( - a xexp(( - ax^2 ) / 2)) + (2ax - 1) (a^2x^2 *exp(( - ax^2 ) / 2)))

Homework Statement ψ2 = A(2αx2- 1)e-αx2/2 First, calculate dψ2/dx, using A for A, x for x, and a for α. Second, calculate d2ψ2/dx2. 3. The Attempt at a Solution so I got the first derivative correct, it was A((4*a*x)*exp((-a*x^2)/2) +(2*a*x^2 -1)*(-a*x*exp((-a*x^2)/2)))...

Homework Statement Show that the energy of a simple harmonic oscillator in the n = 2 state is 5Planck constantω/2 by substituting the wave function ψ2 = A(2αx2- 1)e-αx2/2 directly into the Schroedinger equation, as broken down in the following steps. First, calculate dψ2/dx, using A for A, x...

For reference the necessary function to calculate this is 1/A - 1/(2πN) x Sin(2πN/3) Where N is the state A is the amount of the box you want Just plug in your limits and solve

Omg how could i be so blind, thank you! the 4th exited state is actually n=5! thanks the answers coming out correct now

Well I've been testing this out with an example I Know the answer to (where N=3) but I'm getting an answer of .306 when it should be .299

still not working, might be missing something else

n should be 4, maybe I'm missing a n in the sine function

Hi as an undergrad Physics student learning quantum mechanics for the first time, I'm having a hard time wrapping my head around quantum tunneling, why does it happen, why can it happen? I was also reading that Graphene exhibits tunneling as well, could someone explain this?