Recent content by DB

simple question, if the derivative of cos(x) as x->0 is 1, the is the derivative of cos(3x) as x->0 = 1 aswell?

thanks everyone, btw hallsofivy displacement is a vector, distance is not. just to cleat that up :) thanks again i understand the problem now

oh I am sorry, it is suposed to say 100m North

sry, i can't find the mistake your talking about, would that 85 be -115?

im not use to working is 3D so i need some help you are going to a restaurant. you leave your apartement and take the elevator 30 m down, then 15 m south to the exit. then u travel 200 m east and then 100 m to the restaurant. what is your displacement. so what i did is: -30k -15j...

finally, got it

thanks for the replies, but i don't understand how the c.d is 2h(2+h)

but those are different terms, arent i looking for a common denominator?

i don't understand

thanks okay stupid mistake, now I am stuck again tho \frac{2}{2(2+h)}-\frac{(2+h)}{2(2+h)}*\frac{1}{h} comes out to \frac{-1}{h}}*\frac{1}{h} gives me -1/h which doesn't work, darn

really isn't calculus but that's the name of my class so, anyway I am having a problem here. i think its pretty simple I am just missing something. I am supposed to find the slope of the tangent line using one point and: slope of tangent line = \frac{f(a+h)-f(a)}{h} h\rightarrow0...

nvrm, the it is F \propto f^2mr thanks tho

doing a lab report on circular motion and was asked to make a combined proportionality statement, just asking yes or no, is this right? F_c \propto f^{2} \propto a_c \propto \frac{1}{m} \propto r where "F_c" is the centripetal force, "f" is frequency in Hz, "a_c" is the centripetal...

are you saying that space is infinite?

I see, so really the notion that the universe is still expanding today is an assumtion?