Recent content by debeloglava
-
D
Electric field at a point on the perpendicular bisector of a finite line charge
I'm not sure what you mean by "segment of charge between x and x+dx". Do you mean a segment of charge, say at x = 3m? This new side to the triangle formed by points (3, 0), (5, 0), and (5, 12) would then be a = 5 - x where x is any value along the x-axis from 0 to 5. I'm using theta to...- debeloglava
- Post #5
- Forum: Introductory Physics Homework Help
-
D
Electric field at a point on the perpendicular bisector of a finite line charge
So I shouldn't compute a value for sin\theta and instead leave it in terms of b and r (sin\theta = b / r = 12 / r)? Then I have (integral from x=0 to x=5 again): Ey = \int k(dq)sin\theta / r3 ... Ey = 12k\lambda / r3 * \intdx ... Ey = 60k\lambda / r3 Then E = 2 * Ey E = 120k\lambda...- debeloglava
- Post #3
- Forum: Introductory Physics Homework Help
-
D
Electric field at a point on the perpendicular bisector of a finite line charge
Homework Statement A uniform line charge of linear charge density \lambda = 5.00 nC/m extends from x = 0 to x = 10m. The magnitude of the electric field at the point y = 12m on the perpendicular bisector of the finite line charge is? Homework Equations E = \intdE = \intk(dq) / r2 Ex =...- debeloglava
- Thread
- Charge Electric Electric field Field Finite Line Line charge Perpendicular Point
- Replies: 5
- Forum: Introductory Physics Homework Help