Recent content by Deevise

I think it's time i went to sleep... Yeh now that you mention the lack of anti-derivative i knew that. I think a good nights sleep will prepare me better for this exam than grinding my head into non-exsistant problems... sorry to waste your time with inane questions lol... Thanks for the...

Well now i feel kind of stupid... its line intergration, not contour integration :P the question reads: Evaluate the integral: \int( \bar{z} +1 ) dz L Where L is the line segment from -i to 1+i. normally i would just integrate and sub in start and end point, but i have totally...

Im doing a bit of contour integration, and a question came up with a term in it am unsure of how to do: in its simplest form it would be \int\bar{z}dz where z is a complex number and \bar{z} is it's conjugate. Hmm i can't get the formatting to work out properly.. :S

I was always of the impression that before you find limits, cancel anything that cancels, then rearange in order to get a form in which finding the limit is obvious... and in both of the limits you give it all cancels out. So either there is a typo, or you are asking for the limit as x tends to...

Hmm.. when you say normal integration, from your example of a normal integral i assume u mean finding the area under a 2D curve, like y=x2 between a pair of bounds. line integration is used when instead of having a function of 1 variable (like f(x) = x2) you have a function of 2 or more...