Recent content by dh743
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Finding Convex Lens Focal Length
Thanks for the reply. So you've multiplied everything by di, but what does that actually show? As in why would you do it? Also, why isn't the gradient simply 1/do since (di/do)/di = 1/do?- dh743
- Post #3
- Forum: Introductory Physics Homework Help
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Finding Convex Lens Focal Length
Homework Statement Following data recorded: Di (distance image to lens) 6.0 8.0 10.0 12.0 14.0 Magnification 0.2 0.6 1.0 1.4 1.8 Graph magnification against di and use the graph to find the focal length of the lens. Homework Equations...- dh743
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- Convex Convex lens Focal Focal length Length Lens
- Replies: 3
- Forum: Introductory Physics Homework Help
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Electric Fields - Net Charge on Point Charges
Thanks for all your help, but I still can't get it to a point where I only have one unknown - I always end up with both q and r as unknowns. And what do the subscript 12 and 13 mean in your above equation?- dh743
- Post #9
- Forum: Introductory Physics Homework Help
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Electric Fields - Net Charge on Point Charges
Ok letting 5 microC be y and 8 microC be z, this is I've ended up with: Ey=\frac{kq}{r2} Ez=\frac{kq}{(0.9-r)2} Eq = \frac{k(5microC}{r2} + \frac{k(8 microC}{(0.9-r)2} I can't solve them because I always end up with 2 unknowns so I must have made a mistake somewhere.- dh743
- Post #7
- Forum: Introductory Physics Homework Help
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Electric field of point charges
Homework Statement A 4microC point charge is placed at the coordinate origin. Two other point charges are placed on the x axis: q1 at x=30cm and q2 at x=50cm. Find the magnitude and sign of q1 and q2 if the net force on each of the three charges is zero. Homework Equations...- dh743
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- Charges Electric Electric field Field Point Point charges
- Replies: 1
- Forum: Introductory Physics Homework Help
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Electric Fields - Net Charge on Point Charges
That makes sense, but how do I now arrange it to avoid having 2 unknowns?- dh743
- Post #5
- Forum: Introductory Physics Homework Help
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Electric Fields - Net Charge on Point Charges
Yeah you're right, it does mean the net force on each charge is zero. How did you get the answer though?- dh743
- Post #3
- Forum: Introductory Physics Homework Help
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Electric Fields - Net Charge on Point Charges
Homework Statement Two point charges are placed on the x axis: +5 microC charge at x=0 and +8 microC charge at x=0.9m. Where on the x-axis can a third charge be placed so that the net charge on all three charges is zero? Determine the magnitude of the third charge. Homework Equations...- dh743
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- Charge Charges Electric Electric fields Fields Net Point Point charges
- Replies: 9
- Forum: Introductory Physics Homework Help
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Derivative of (2x^2 + 1)x^(1/2) using Product Rule | Homework Question
Homework Statement Find the derivative of y= (2x2 + 1) x1/2 Homework Equations Product RuleThe Attempt at a Solution After differentiating, I eventually get stuck at: \frac{4x3/2+2x2+1}{2\sqrt{x}} The given solution is \frac{10x2+1}{2\sqrt{x}}- dh743
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- Product Product rule
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Simplify Homework: (2n+4 - 2 x 2n) / (2n+2 x 4) | 7/8
Thank you it makes sense now.- dh743
- Post #5
- Forum: Precalculus Mathematics Homework Help
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Simplify Homework: (2n+4 - 2 x 2n) / (2n+2 x 4) | 7/8
Thanks for replying and I've added some brackets (the question didn't have any). Wouldn't the numerator be 2^{n+4}- 2^{n+1}?- dh743
- Post #3
- Forum: Precalculus Mathematics Homework Help
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Simplify Homework: (2n+4 - 2 x 2n) / (2n+2 x 4) | 7/8
Homework Statement Simplify: (2n+4 - 2 x 2n) / (2n+2 x 4)Homework Equations N/AThe Attempt at a Solution (2n+4 - 2n+1) / (2n+4) Unsure where to go from here, but the given answer is 7/8 Thanks for any help- dh743
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- Replies: 4
- Forum: Precalculus Mathematics Homework Help
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Kg m/s Change in Momentum of Trolley
Thanks for your help but i ended up with the correct answer but negative (-1.8). Would this be correct in this situation? I would have thought an increase in mass (the object) would mean an increase in momentum.- dh743
- Post #5
- Forum: Introductory Physics Homework Help
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Kg m/s Change in Momentum of Trolley
the answer I've got is 1.8- dh743
- Post #4
- Forum: Introductory Physics Homework Help
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Kg m/s Change in Momentum of Trolley
Homework Statement A 2.4kg cart is moving with a constant speed of 2m/s along a smooth horizontal plane when a 1.5kg object is dropped vertically onto it. What is the change in momentum of the trolley? Homework Equations p=mv \Deltap=p final - p initial The Attempt at a Solution...- dh743
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- Change Change in momentum Momentum
- Replies: 5
- Forum: Introductory Physics Homework Help