Homework Statement
My teacher has notes online that say:
A Simple Construction Technique for WellFounded Orders
Any function ƒ : S→N defines a wellfounded order on S by
x < y iff ƒ(x) < ƒ(y).
Example:
Lists are wellfounded by length. Binary trees are wellfounded by depth, by number of nodes...
Okay so this is what I got:
Fk+1(Fk - Fk-1) + F2k
Fk+1(Fk - Fk - Fk - 1) + F2k
-Fk+1Fk-1 + F2k
Multiply by -1 and get:
Fk+1Fk-1 - F2k = -(-1)k+1
So P(k) = -(-1)k+1
The part about the -1 on the right hand side threw me off at the end but I think it makes sense.
It seems unusual that this...
Thank you for your reply.
With that I get:
FkFk+2 - F2k+1
Fk(Fk+1 + Fk) - F2k+1
FkFk+1 + F2k - F2k+1
Fk+1(Fk - Fk+1) + F2k
I'm not really sure where to go from this point.
Just to verify that I am thinking of this the right way.
I am trying to find a spot that I can use the assumption made...
Homework Statement
The fibonacci numbers are defined by F0 = 0 F1 = 1 and Fn = n-1 + Fn-2 for n >= 2.
Use induction the prove the following:
Fn-1Fn+1 - Fn = (-1)n
The attempt at a solution
Let P(n) = Fn-1Fn+1 - Fn2 = (-1)n where n>= 1
Show it holds for first natural number:
P(1) = F0 + F2 -...
Homework Statement
I am trying to prove the absorption law
A U (A ∩ B) = A
I know that a way to prove this is to show that each is a subset of the other but I'm a little confused about one part in the process (below)
Homework EquationsThe Attempt at a Solution
Let x∈A U (A ∩ B)
then x∈A or...
Homework Statement
The Rockwell hardness of certain metal pins is known to have a mean of 50 and a standard deviation of 1.5.
a)if the distribution of all such pin hardness measurements is known to be normal, what is the probability that the average hardness for a random sample of 9 pins is at...
Homework Statement
Five companies (A,B,C,D and E) that make electrical relays compete each year to be the sole supplier of relays to a major automobile manufacturer. The auto company's records show that the probabilities of choosing a company to be the sole supplier are
Supplier chain: A B...