Recent content by dlp211

Yes that is the center of mass equation. The 0.5 comes from the uniform rod of 1m.

Thanks

Wait, is supposed to be distance to center mass? The lecture notes don't say this, but I think this is right. [1.5(.5)+1.5(1.0)]/3 = .75

I thought d was distance, but I am guessing that it isn't?

Homework Statement A physical pendulum consists of a small 1.5kg mass at the bottom end of a uniform 1.00m long 1.5kg stick swinging about its upper end. The moment of inertia of the pendulum about its upper end is 2.00kg*m^2. What is the angular frequencyHomework Equations sqrt(mgd/I)=w I...

Thanks guys, This was the end of a much larger problem and it now makes sense that I need to use the Newton's Method(this is was the end of a Calc II) problem. It's been a long time for some algebra concepts for me so I appreciate all the help. Dave

Homework Statement 3b^(2/3) - 2b = 10/16 Find solution to a precision of thousanths The attempt at a solution I know the answer is ~ .199, I do not however know how to actually solve the above equation. If anyone can help, I'd appreciate it, it's been over 10 years since I took...

Which I now was able to reduce to: x(x1/2-x) / x(x+1) which goes to: (x1/2-x) / (x+1) and so my limit is 0/1 which is zero. Anyone want to check the work I would greatly appreciate it.

I have manipulated the equation to: x1/2(x+1) - (x2+x)1/2 / x(x+1)

Homework Statement lim x->0+ 1/x1/2 - 1/(x2+x)1/2 Homework Equations inf - inf The Attempt at a Solution I can't get x out of the bottom of the equation.

Thanks for the help! My lectures go so fast and I have a hard time following all the formulas.

so a(t) = 9.6 - 3.0t^4? so a(t) = 9.6 m/s^2?

I thought that the derivative function would be 9.6t - .6t^5. But I haven't actually learned derivatives yet.

delta x/delta t as t -> 0 is 2.17 (edit: this is wrong). It's because 2.17 is the starting point. I don't know how to solve 2nd derivatives, I barely know anything about derivatives, our physics course is moving faster then our calc course right now.

Homework Statement The position of the front bumper of a test car under microprocessor control is given by: x(t) = 2.17 + (4.80m/s^2)t^2 - (0.100 m/s^6)t^6 Find the acceleration at the first instant when the car has zero velocity. Homework Equations The Attempt at a Solution 0m/s^2...