Recent content by dodosenpai

So at the top the normal, gravity and centripetal force are all acting downwards while the centrifugal force acts outwards? So the force of the ball on the track would be the centrifugal force - normal force since the centripetal force should be provided by gravity?

Nevermind they aren't

Gravity and the Normal Force, both pointing downwards and equal in magnitude

Homework Statement A small disc, radius r and mass m = 7.9 g, rolls on its edge. The friction with the track is enough to prevent slipping. When released, it rolls down the track (sketch) and reaches a circular section with radius R = 5.1 cm, which is very much greater than r. The initial...

Thanks

So that would be that the contact force is not horizontal, but instead has a magnitude of √((0.84*19)2+(19)2) = 24.81 = 25N at an angle of tan-1(0.84) = 40.03 = 40°?

So that would be that the contact force is not horizontal, but instead has a magnitude of √((0.84*19)2+(19)2) = 24.81 = 25N at an angle of tan-1(0.84) = 40.03 = 40°?

Homework Statement In this sketch, the mass m = 1.6 kg is pushed against a wall by force F, as shown, in the horizontal direction. The values of the coefficients of kinetic and static friction for the contact between are 0.81 and 0.84 respectively. The magnitude of F is slowly and continuously...