Recent content by doub

I not certain but I think I would go about solving it like this; The formula you want to use is v'A = ((mA-mB)/(mA + mB))vA And look at the frame set so that the total velocity of block 1 is actual 10 m/s - 5 m/s so the sped of block one would be 5 m/s. No guarantee though

You have all the info I believe...Look at hess's law and at the net ionic equation. I have posted what I believe the answer to be...

All messages are transmitted the same way through the nervous fibers. When the nerve fiber is stimulated it creates an action potential that travels along the nerve pathway, or depending on the structure will jump quickly along the nerve generating action potentials at the node of ranvier. The...

Hello Everyone, I am having a heck of a time with collisions in 2D and with rotational kinetics and rotational dynamics. I have posted 5 questions below that I seem to be having the most troubles with. I know it my be a lot to ask but if anyone here can help me to understand how they got to...

The best I can get is \alpha = (T1 + T2)/I = (Fr - Tr)/1/2 mr2 = (mra -(ma+mg)r)/ 1/2 mr2 don't see how the radiii cancel each other though

so if we add are we left with; (v12 -v12'cos302) + (-v12'sin302) / 2v2'2 ?

I am just not seeing this... cos2(θ) = (v12 -v12'cos302)/v2'2 sin2(θ) = (-v12'sin302)/v2'2 thanks very much for helping btw

So, cos(theta) = v1 - (v1'cos30)/v2' and sin(theta) = (-va'sin30)/v2' where do the sin2theta come from?

Ok, The equations I have gotten are x --> v_1 = v_1'cos30 + v_2'cos(theta) y --> 0 = v_1'sin30 + v_2'sin(theta) Energy --> v_1^2 = v_1'^2 + v_2'^2

Homework Statement A light string is wrapped around a solid cylinder and a 300 g mass hangs from the free end of the string, as shown. When released, the mass falls a distance 54 cm in 3.0 s. Calculate the mass of the cylinder? Homework Equations not sure The Attempt at a...

yeah I'm totally lost now

Right, this is the best answer I got however I do not feel anywhere near confident. 3.0 m/s = v_1'cos30 + v_2'cos(theta) = 2.598 m/s + v_2'cos(theta) = 3.0 m/s - 2.598 m/s so v_2'cos(theta) = 0.402 m/s in the "x" direction 0 = v_1'sin30 + v_2'sin(theta) = 1.299 m/s + v_2'sin(theta). so...

Homework Statement A 2.0 kg ball moving with a speed of 3.0 m/s hits, elastically, an identical stationary ball. If the first ball moves away with an angle 30 degrees to the original path, determine the speed of the first ball after the collision, and the speed and direction of the second...

I know the two mass values, however we do not know the radius of the pulley. In the first trial the m1 mass is 122.59 g and the m2 mass is 113.46 g with the accelerations calculated as 0.07 m/s^2 Trial 2 m1 mass 124.34 g m2 mass 111.71 g with the acceleration calculated as 0.21 m/s^2...

Homework Statement The question is from a lab. The lab used an Atwood Machine with two masses suspended string looped over a pulley. The time for one mass to reach the ground was measured and acceleration of the mass was calculated. The results were plotted on a graph of weight difference...