Recent content by Dr Meow

Would that be the rotational acceleration around point A?

Even then I end up with -24.325 which is wrong.

So would it end up being tan(α) = (11)*sin(80)/[(8 + 11)*cos(80)]? Then (α - 30) Because when I computed that all out it ended up to be the wrong answer.

Ok. So here's what I've done: To get the magnitude I drew a diagram of the 30 degree angle downwards and the 50 degree angle upwards. Then combined them to make a total of 80 degrees and used law of cosines to find the hypotenuse of the total triangle created and found that to be 14.29, which is...

I'm sorry, but I'm still a little lost on what you mean. I know how to do trig but I don't really understand the terminology. By components would you mean to use sin30=x/150 in order to get the opposite length for the force in quadrant 1?

Sorry, my attempts at a solution only led me to the fact that Tension=MfG-MfA and then Tension=1/2McA and therefore MfG-MfA=1/2McA. "A" being acceleration, Mf being Mass of Fred, and Mc being mass of the cylinder and G being gravity.

Homework Statement A 13-kg solid steel cylinder with a 10-cm radius is mounted on bearings so that it rotates freely about a horizontal axis. Around the cylinder is wound a number of turns of a fine gold thread. A 4.0-kg monkey named Fred holds on to the loose end and descends on the...

By vector form do you mean to find the opposite of each angle's side length? As in the O for SOH CAH TOA?

Homework Statement Four forces act on bolt A as shown. Determine the net force (in Newtons) and direction (in degrees upward from the x-axis) acting on the bolt. Homework Equations Law of Sines: a/sinA = b/sinB = c/sinC Law of Cosines: a^2= b^2 + c^2 - 2bccosAThe Attempt at a Solution I...

Hey sorry it's taken me so long to reply I had forgotten about this. To be honest I did forget how I found the magnitude. And I'm still not sure because it's been even longer. Is there a way you could help me do just the degrees to the horizontal? Thanks

I'm sorry, I didn't understand what you really meant by the resultant in this case. When you said solve for the resultant.

Isn't the resultant just the horizontal line? I'm sorry I did this problem a while ago and I don't remember how I did it. And the reason for the accuracy is because I'm doing this problem on WebAssign and you can't round to put in the right answer.

Homework Statement Use the cosine and sine rules to determine the magnitude and direction of the resultant of a force of 11 kN acting at an angle of 50 degrees to the horizontal and a force of 8 kN acting at an angle of -30 degrees to the horizontal. Homework Equations Law of Sines...