Calculating Net Force and Direction on Bolt A

Click For Summary
SUMMARY

The discussion focuses on calculating the net force and direction acting on bolt A, utilizing the Law of Sines and the Law of Cosines. Participants emphasize the importance of determining the vector components of each force in both the x and y directions, expressed as F = F_x i + F_y j. Trigonometric functions are essential for resolving the forces, particularly in identifying the opposite side lengths using sine and cosine ratios. The conversation highlights the need for clarity in terminology related to vector components and trigonometric applications.

PREREQUISITES
  • Understanding of vector components in physics
  • Familiarity with trigonometric functions (sine, cosine)
  • Knowledge of the Law of Sines and Law of Cosines
  • Basic skills in resolving forces in two dimensions
NEXT STEPS
  • Study vector decomposition in physics
  • Practice problems using the Law of Sines and Law of Cosines
  • Learn to apply trigonometric functions to resolve forces
  • Explore examples of net force calculations in two-dimensional systems
USEFUL FOR

Students in physics, engineers working with force analysis, and anyone needing to calculate net forces in mechanical systems.

Dr Meow
Messages
13
Reaction score
0

Homework Statement



Four forces act on bolt A as shown. Determine the net force (in Newtons) and direction (in degrees upward from the x-axis) acting on the bolt.

72559.jpg


Homework Equations


Law of Sines: a/sinA = b/sinB = c/sinC
Law of Cosines: a^2= b^2 + c^2 - 2bccosA

The Attempt at a Solution


I am totally lost, I really don't know where to even start.
 
Physics news on Phys.org
You can start by finding the vector form for each force.
How would then find the TOTAL force?
 
By vector form do you mean to find the opposite of each angle's side length? As in the O for SOH CAH TOA?
 
Dr Meow said:
By vector form do you mean to find the opposite of each angle's side length? As in the O for SOH CAH TOA?

I mean the components for each vector, in the y and x direction.
\vec{F} = F_x i + F_y j.
You will have to use trig.
 
Winzer said:
I mean the components for each vector, in the y and x direction.
\vec{F} = F_x i + F_y j.
You will have to use trig.

I'm sorry, but I'm still a little lost on what you mean. I know how to do trig but I don't really understand the terminology. By components would you mean to use sin30=x/150 in order to get the opposite length for the force in quadrant 1?
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
30
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
10
Views
1K