Calculating Net Force and Direction on Bolt A

AI Thread Summary
To calculate the net force on bolt A, one must first determine the vector components of each force acting on it. This involves breaking down the forces into their x and y components using trigonometric functions. The discussion emphasizes the importance of using the Law of Sines and the Law of Cosines for solving the angles and sides of the forces. Participants express confusion about terminology and the process of finding the total force, particularly regarding the use of sine and cosine to identify vector components. Understanding these concepts is crucial for accurately calculating the net force and its direction.
Dr Meow
Messages
13
Reaction score
0

Homework Statement



Four forces act on bolt A as shown. Determine the net force (in Newtons) and direction (in degrees upward from the x-axis) acting on the bolt.

72559.jpg


Homework Equations


Law of Sines: a/sinA = b/sinB = c/sinC
Law of Cosines: a^2= b^2 + c^2 - 2bccosA

The Attempt at a Solution


I am totally lost, I really don't know where to even start.
 
Physics news on Phys.org
You can start by finding the vector form for each force.
How would then find the TOTAL force?
 
By vector form do you mean to find the opposite of each angle's side length? As in the O for SOH CAH TOA?
 
Dr Meow said:
By vector form do you mean to find the opposite of each angle's side length? As in the O for SOH CAH TOA?

I mean the components for each vector, in the y and x direction.
\vec{F} = F_x i + F_y j.
You will have to use trig.
 
Winzer said:
I mean the components for each vector, in the y and x direction.
\vec{F} = F_x i + F_y j.
You will have to use trig.

I'm sorry, but I'm still a little lost on what you mean. I know how to do trig but I don't really understand the terminology. By components would you mean to use sin30=x/150 in order to get the opposite length for the force in quadrant 1?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top