Use the cosine and sine rules to determine the magnitude and direction of the resultant of a force of 11 kN acting at an angle of 50 degrees to the horizontal and a force of 8 kN acting at an angle of -30 degrees to the horizontal.
Law of Sines: (a/sinA) = (b/sinB) = (c/sinC)
Law of Cosines: b^2 = a^2 + c^2 - 2*a*c*cosB
The Attempt at a Solution
Ok, so I actually already solved for the magnitude to be 14.29783742 kN. But the other blank for the question is for "degrees to the horizontal". I may not be understanding the term correctly but I have no real idea of how to solve for this.