Recent content by draotic

masses are same , no friction anywhere , no MI of pulley

Homework Statement 1 / (3√x2 ) Homework Equations The Attempt at a Solution the overall power of x in denom becomes ( 1/2 * 2 * 1/3 = 1/3) taking in num , it becomes (-1/3 + 1 = 2/3) so answer should be x2/3 / (2/3) which is wrong , please help

thanks tiny-tim and azizlwl for helping me out .. azizlwl's reason seems quite right to me.. in B1 , only tension is involved ( ignoring kinetic friction ) and in B2 , we must have tension + centripetal force . . so B1 must hit pulley first..

thanks tiny-tim and azizlwl for helping me out .. azizlwl's reason seems quite right to me.. in B1 , only tension is involved ( ignoring kinetic friction ) and in B2 , we must have tension + centripetal force . . so B1 must hit pulley first..

well the angle will vary from 0 to pi/2 , so are we going to involve integration ?

sorry , i didnt quite get it .. . which angle are we concerned about?

Homework Statement Given in the pic .. . Homework Equations F=mg The Attempt at a Solution i think block 2 hitting wedge will take place 1st as the direction of displacement of B1 is perpendicular to 'g' .. . but i don't think that's a logical answer please answer and explain why

ok , i think i got it thank you very much sir... appreciate what you are doing !

please help me to understand how to calculate resistances in arms like the above e.g. .

i got it until ' R P(1) = 3 ohm ' but shouldn't the effective resistance of arm ADE be 6+3=9 and effect. resistance b/w A & E be (9*6) / 9+6 = 54/15 ?

next number in pattern 6 , 4 , 3 , 12/5 ... 1) 7/3 2) 9/4 3) 13/5 4) 2 please explain your deduction too thank you

Homework Statement find the sum of the series to 'n' terms (1^3 / 1 ) + (1^3 + 2^3 / 1+2 ) + (1^3 + 2^3 + 3^3 / 1+2+3 ) +... Homework Equations sigma n^2 = n(n+1)(2n+1) / 6 sigma n = n(n+1) / 2 The Attempt at a Solution numerator = 1^3 + 2^3 + ... n^3 denominator = 1+2+3+...n...

could you please do it for 1 rectangle , i'll do rest

all right , 3 pieces have area 2b^2 and the larger one has 5b^2 what now?

thats where i am going wrong... dont know how to proceed , grateful if you could take it from here