Recent content by drpepper0708

Thank you everyone for your help in pointing out my mistake, it helped me narrow in on the solution.

I figured it out, here it is Using \gamma^{\nu}\gamma^{\rho}=2g^{\nu\rho}-\gamma^{\rho}\gamma^{\nu} we have \gamma^{\mu}\gamma^{\nu}\gamma^{\rho}=\gamma^{\mu}\left(2g^{\nu\rho}-\gamma^{\rho}\gamma^{\nu}\right) =2\gamma^{\mu}g^{\nu\rho}-\gamma^{\mu}\gamma^{\rho}\gamma^{\nu} next we...

We have to prove the identity, other identities are allowed, but for obvious reasons not that one

here is what I have so far \gamma^{5}\gamma^{\rho}=\frac{i}{24}\epsilon^{\sigma\mu\nu\rho}\gamma_{\sigma}\gamma_{\mu}\gamma_{\nu}\gamma_{\rho}\gamma^{\rho}=\frac{i}{6}\epsilon^{\sigma\mu\nu\rho}\gamma_{\sigma}\gamma_{\mu}\gamma_{\nu}...

Wiki identities and other identities are allowed, I am trying to start by expressing \gamma^{5}=\frac{i}{24}\epsilon^{\mu\nu\rho\sigma}\gamma_{\mu}\gamma_{v}\gamma_{\rho}\gamma_{\sigma} from which it follows that...

I need help proving the identity \gamma^{\mu}\gamma^{\nu}\gamma^{\rho}=\gamma^{\mu}g^{\nu\rho}+\gamma^{\rho}g^{\mu\nu}-\gamma^{\nu}g^{\mu\rho}+i\epsilon^{\sigma\mu\nu\rho}\gamma_{\sigma}\gamma^{5}