Recent content by Duncan1382

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    How Is Work Calculated in a Vector Field?

    Homework Statement Find the work done by the force field F in moving an object from P to Q. F(x,y,z)=10y^(3/2)i+15x\sqrt{y}j P(1,1), Q(2,9)Homework Equations W = \intF dot drThe Attempt at a Solution I have no clue how to do it
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    Calculating Electron Deflection in a Ballistic Electron Transistor

    Homework Statement In nanoscale electronics, electrons can be treated like billiard balls. The figure shows a simple device currently under study in which an electron elastically collides with a rigid wall (a ballistic electron transistor). The green bars represent electrodes that can apply...
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    Understanding Implicit Differentiation: Solving for Second Order Derivatives

    You can't express y in terms of x. It's not a function. You can express it in terms of x and y, but that just makes the math longer.
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    Understanding Implicit Differentiation: Solving for Second Order Derivatives

    Find d^2/dx^2(3y^2+8y=3x) I managed to get dy/dx = 3 / (6y + 8) but I have no clue where to go from here. According to WolfRamAlpha, the answer is -27/(4(16 + 9x)(4 + 3y)), but since dy/dx doesn't have any x value in it, I don't see how the derivative of it would. I've played around...
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    Minimum Speed of a Rock: Solving Problem with Pit Gap of 40m

    I'm not sure if this is right, but this is what I came up with: 1) I found the speed that the object needed to be going to clear the jump.. not too hard. I assumed the ground was horizontal at the launch angle. 2) I used Energy to solve the problem. Speed to Clear: \Deltay = .5at2 -20m...
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    Derivative Help: Understanding x2+x

    You've just got to learn the rules of derivatives. The derivative is: f(x) = 2x + 1 for the first one, pull out the exponent and make it a coefficient while lowering the exponent by 1 degree. Same thing for the second term.
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    Deceleration and reaction time physics problem

    Okay, I'll walk you through it in words and see if you can solve it with numbers... 1) Subtract the distance that you "react" from the total distance between you and the deer to get to the point when you start to "decelerate" (tell your teacher that's a bad word -- use "negative acceleration")...
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