Derivative Help: Understanding x2+x

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Homework Statement


Ok, I am learning about derivative's, and they seem to elude me for some reason. I have this.

x2+x

I know the derivative is 5, and the function is differentiable at 2. But I don't understand how you get it. I know the limit you use to find it, but the shortcut is nxn-1 right? Where does n come from? And x=2 right? Would it be 2*21? But that's not 5, its 4. What am I doing wrong? Please, detailed answers are very very appreciated.


Homework Equations


Pretty sure that I noted all the nessicary equations above.


The Attempt at a Solution


I said what I attempted above.
 
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schlynn said:

Homework Statement


Ok, I am learning about derivative's, and they seem to elude me for some reason. I have this.

x2+x

I know the derivative is 5, and the function is differentiable at 2. But I don't understand how you get it. I know the limit you use to find it, but the shortcut is nxn-1 right? Where does n come from? And x=2 right? Would it be 2*21? But that's not 5, its 4. What am I doing wrong? Please, detailed answers are very very appreciated.


Homework Equations


Pretty sure that I noted all the nessicary equations above.


The Attempt at a Solution


I said what I attempted above.
You've just got to learn the rules of derivatives.

The derivative is:

f(x) = 2x + 1

for the first one, pull out the exponent and make it a coefficient while lowering the exponent by 1 degree. Same thing for the second term.
 
The original function x^2+x can be seen as x^2+x^1

n is the exponent for each x, so for the first x, n=2 and n=1 for the second x

then use the derivative formula which is dy/dk of f(x) = nx^(n-1)

which would mean the derivative is 2x^(2-1)+1x^(1-1) which equates to 2x^2+1

since it asks what the value of dy/dx is at x=2, you plug 2 into the derivative for an answer of 2(2)+1 which equals 5
 
Thank you so much.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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