Recent content by Emilyneedshelp

3cos(65)W-2tan(25)sin(25)Fr-2cos(25)Fr=0 335.7(3)cos65=Fr(2tan(25)sin(25)+2cos(25)) Fr = [335.7(3)cos65]/(2tan(25)sin(25)+2cos(25)) Fs = Fr*cos25 = Fnμ Fn = W-Fr*sin25 μ=(Fr*cos25)/(W-Fr*sin25) μ=.688 ANS Thank you for the help it was the correct answer.

F(rol)cos25=Fs=Fnμ Fn=W Σt=0=w*d1-F(rol)cos(25)d2 d1=(L/2)sin(65) d2=h w*d1=F(rol)cos(25)d2 w*d1/d2=F(rol)cos(25) F(rol)cos(25)=Fnμ (W(d1))/2=Wμ Getting 1.5 out for μ which is ridiculous. I feel like my issues lies with the d1 selection. I tried it with cos(65) too and still a wrong answer...

I'm sorry about that, I thought the post above had posted an answer too.

The force of the roller is perpendicular to the to the board, using this I got it to F(rol)cos(25) Fn=W*d - F(rol)cos(25) But now I am confused what to do.

(366-266)+(367-267)+(368-268) Is the answer I was talking about.

There seems to be no restraint on having a password of only numbers, your reasoning creates this restraint. 366 will give you all the possible passwords for a six character long passwords containing 0-9 and a-z (note: passwords only containing letters are still in the mix.) Now you need to find...

Homework Statement A board that is of length L = 6.0 m and weight W = 335.7 N rests on the ground and against a frictionless contact at the top of a wall of height h = 2 m (see figure). The board does not move for any value of greater than or equal to 65 degrees but slides along the floor if...

Thank you, I solved it. How silly of me not to realize that.

Homework Statement Question A car starts from rest and uniformly increases its speed at a rate of 0.7 m/s2 on a circular track of radius R = 253 m. What is the magnitude of the car’s net acceleration after 50 s? acen=.7m/s^2 t=50s R=253m Homework Equations Equations acen=(v^2)/r Maybe...