Recent content by EmmaK

ok.. i just used trig. sin(angle) = opposite/hypotenuse. want to find hypotenuse and opposite =h. and there's 2 of these triangles, so path difference is double this..hard to explain without a diagram!

oh ok, is the path difference not 2hsin(theta)=300sin(theta) either?

anyone?

got it :)

Still not working lol! must be doing something really stupid

Homework Statement In a scattering experiment the square-root of (i)Consider a proton of (relativistic) energy,E, incident on another proton in a stationary target. Show that in this case, s= 2m_p(m_p+E/c^2) where m_p is the proton mass. (ii)Now consider 2 protons traveling with equal and...

Homework Statement A radiotelescope is positioned at a height of h=150m on a cliff overlooking the sea. A very distant galaxy emitting radiowaves, wavelength 3m, is at an angle \theta above the horizion. The radiowaves reach the telescope both directly and after reflection off the water...

ahhh ok thanks, so which doesn't change its profile. i thought 2 as it would keep repeating, but the actual height would be constantly changing

not really. isn't 5 the frequency? actually no.. because that would mean y1 has a frequency of 0...

for (ii) i have just differentiated and subbed it into the wave equation and got v= 0.5i. can you have and imaginary wave speed?

Homework Statement Consider y_1=Asin(5x)exp(-2t) y_2=Aexp(4ix)exp(-2it) y_3=Asin(2x-5t)exp(-2t) (i)which one represents a wave that propagates at constant speed with no change in its profile (ii)Confirm it satifies the wave equation and obtain the wave velocity (iii)Comment...

ok...but how do i differentiate -a_x(t) ? ohhh, it's just -(the x -component of j x a)?

ahh i meant to write 'is it just -a_x' can you integrate both sides? so da_z/dt is -a_x t , which is a function of t??

tried it again... U_0 =1/2 C_0 V^2 and U_1 =1/2 C_1 V^2 [itex] C_1 = 1/2 \epsilon[/tex]r so [itex] U_1 =1/2 *1/2 C_0 \epsilon[/tex]r V^2 [itex] =1/2 \epsilon[/tex]r *U_0 ?

I need to differentiate a_z (t) with respect to t... can i just say it's -a_x ?