yeah, I know...but our homework is on a computer program (CAPA), and after using 7 out of 10 tries on this problem I called a classmate and he said that he did it without the cos squared...so I tried it and it was finally marked correct!...not really sure what's going on with this problem!
I have finally solved it! So my Erms equation was correct. My intensity was not...
Turns out what I had to do was not square the cos...
so instead of I = Iocos227.5
the equation is:
I = Iocos27.5 = 11.7085
Which I can then plug into the equation for Erms above
Thanks for your help!
Homework Statement
A beam of polarized light has an average intensity of 13.2 W/m2 and is sent through a polarizer. The transmission axis makes an angle of 27.5° with respect to the direction of polarization. Determine the rms value of the electric field of the transmitted beam...
I guess I should have put all of the equations that I have in the first post, but they're a little difficult to type out...but I'll try! Hope this is more clear of the point that I'm at...
P1xi = m1|V1i|cos\theta
P1yi = -m1|V1i|sin\theta
P2xi = m2|V2i|cos\theta
P2yi = m2|V2i|sin\theta...
I guess my problem is trying to figure out the angles. When my professor did a fairly similar problem in class, he ended up with an angle that I'm unclear of how he got that angle. Can someone please tell me exactly how to figure out the angles. I can use my equations if I had the angles.
Using the final velocity, I used the following calculations to try to calculate the initial velocity...
Vi = (1500+1100)/1500 x (13.24)(cos53)
Vi = 13.81 km/hr
Unfortunately, this is not the answer, and I'm really not sure why! Someone please help!
I have drawn a diagram of the two cars. I also used the following calculations to determine final velocity: (which I'm not completely sure is correctly)
sin53 = (1100 x 25)/((1500 + 1100)Vf)
2600Vf = (1100 x 25)/sin53
Vf = (1100 x 25)/(2600 x sin53)
Vf = 13.24 km/hr
I'm unsure how to...
Homework Statement
An Escort and a Camaro traveling at right angles collide and stick together. The Escort has a mass of 1100 kg and a speed of 25 km/h in the positive x direction before the collision. The Camaro has a mass of 1500 kg and was traveling in the positive y direction. After the...
Okay I just solved it! I added the work done by the applied force to the work done by the weight of the crate. The answer is 25 J...I didn't realize that it was so simple!
Thanks for your help!
The forces acting on the crate include the applied force and mg. I'm not sure how they work together in an equation...
I tried just W=Fd using 100.4N as the the F but I know that is not right
Homework Statement
To push a 33 kg crate up a frictionless incline, angled at 15° to the horizontal, a worker exerts a force of 100.4 N, parallel to the incline. As the crate slides 1.50 m, (a)how much work is done on the crate by the worker's applied force? (b) How much work is done on the...