Recent content by enian

I was wondering, why don't we have to define a ground? I am using a program Pspice to check my answers to similar problems and it always makes me define a ground. Yet, circuits like a flashlight obviously don't need a ground node. Perhaps I'm doing something wrong on the program.

Okay, so I redrew it to try and get a better perspective but I am questioning where the nodes are in the circuit, do I do as follows? I wonder then how I'm to find resistance. http://img158.imageshack.us/my.php?image=pic2rc9.jpg

with no interest, paying 5000/year. it would take 80000/5000 = 16 years to pay it off. it's going to be more than that with interest

Homework Statement http://img126.imageshack.us/img126/6400/picex8.jpg" Determine the maximum power that can be delievered to the varaible resistor R in the circuit of Fig 4.139. Homework Equations The Attempt at a Solution I am not sure how to handle this because the...

If you compare yourself to others you may become vain and bitter, for always there will be greater and lesser persons than yourself. Enjoy your acheivements as well as your plans... On my take, many people learn at different levels. There are too many variables at play to say whether one is...

Is my method right though?

Homework Statement An old oaken bucket of mass 6.75 kg hangs in a well at the end of a rope. The rope passes over a frictionless pulley at the top of the well, and you pull horizontally on the end of the rope to raise the bucket slowly a distance of 4.00m. (a) How much work do you do on the...

Homework Statement Each edge of a square has length L. Prove that among all squares inscribed in the given square, the one of minimum area has edges of length \frac{1}{2}L\sqrt{2} Homework Equations The Attempt at a Solution I started by drawing a square of sides L. Then labeled...

Yea I see what you mean. This may be a dumb question but how is k_{n} ever going to become k_{n+1} since we don't know what k is?

Where did the 9.3 come from? or was it supposed to be 9(3^{2n}) The only ways I see to factor that is either by factoring it leaving you with 9(3^{2n} - 1/9) or, by adding the - 1 to the other side.. ? I think you're suggesting I substitute the 3^{2n} - 1 for some expression that is a...

Well, that's what I was trying to do. I don't see how your advice helps.

\frac{(3^{2n})(9)-9}{8} = 9k so from this.. 8(\frac{(3^{2n})(9)-9}{8}) = 8(9k) 3^{2n}(9)-9} = 72k 3^{2n}(9)} = 72k+9 3^{2n}(9) = 9(8k+1) 3^{2n}(9) = 3^{2n}(9) 1 = 1? I'm lost. lol

Okay so.. 3^{2n}-1 = something*8 3^{2n}-1 = 8(k) \frac{3^{2n}-1}{8} = k We want to show that \frac{3^{2(n+1)+1}-1}{8} = multiple.of.8 9(\frac{3^{2n}-1}{8}) = 9(k) \frac{3^{(2n+2)}-9}{8} = 9k \frac{(3^{2n})(3^{2})-9}{8} = 9k \frac{(3^{2n})(9)-9}{8} = 9k Am I headed in the...

Hmm, mod 8? We never covered that in class so I wasn't sure of the notation. So I have 3^2n = 1 mod 8 as my P(n) statement and now I need to show that the statement is also true for 3^2(n+1) = 1 mod 8. So I multiply both side by two three's (or 9) to get the + 1 portion of the exponent...

Homework Statement Prove by induction that, 3^(2n) - 1 is an integral multiple of 8 for all positive n >= 1. Homework Equations 3^(2n) - 1 The Attempt at a Solution First I plugged in some values for n.. Some values I plugged in (1) 3^2(1) - 1 = 8 (2) 3^2(2) - 1 = 80 (3)...