Recent content by fableblue

Yes, that was because i was told that a force/torque is the same anywhere in the post. It seemed to easy for me that is why I did not have faith in my result and all a long is was the way i was checking it. Thank You

I did some switching around of things to try and make it fit:shy: So are you saying that my intial results are correct? How do i go about checking this? I substitute 176.04 in for F and they do not = each other. 7840 = ...wait a minute...:eek: SHAZAM>>>>:bugeye: I was checking my solution...

:cry:deep breath, ok i should have looked at my drawing because then i would have seen that \angleEDC and \angle ECD were not oppisite interior angles:blushing:. What i did this time was use 180-81.25 for \angleEDC=98.75 and then i used the law of cosins to find side EC =130.78 and from there i...

OK so r=\sqrt{(8^2 + 52^2)}=52.61 in the Mp=rFsin\Theta; substitute- 7840 lb in = 52.61sin81.25F; do algebra and F=147.29 lbs= tension in cable ABC. Is this correct? How do i go about checking it?

Thank you, I also was looking at that angle, actually i was looking at ALL the angles:wink:. But now i can see why. And i am going to assume, from your reply, that the angles are valid no matter if the post is leaning or straight. Now that i think about it the problem is looking for the...

Not really:blushing: but thanks, tiny-tim. May be when you are able to see the attachment you see what/where my problem lies. I am going to try it again later on with the use of the law of cosins. What is throwing me off is the pole not being straight. Can I use\angleEDC, which is at the...

Excellent:smile: I have never thought of that, now i know. thank you

Thanks, but that does not really show why it would be different. I am thinking that it has to do with when you sum forces you are looking for a total/resultant of the two forces as apposed to when you are looking for a single force, as in the attachment question 002, you use the unmodified...

Thanks rl.bhat for you response but iI am still in question. I am attaching 2 documents (because it is easier then trying to type them in). 1 is the proff of the law of cosins and the other is another problem that i have done using the Law of Cosins that i was taught and used in trig. This...

I am not sure if this question should be in here but it does pertain more to these problems as compared to a general math question. So, could someone explain why when using the parallelogram rule for obtaining the sum of 2 forces by the means of the Law of Cosines that the controller -2bc is...

Homework Statement It is known that a force with a moment of 7840 lb in about D is required to straighten the fence post CD. If a=8in. ,b=52 in., and d=112 in., determine the tension that must be developed in the cable of winch puller AB to create the required moment about point D...

I was going about this the wrong way, making it too complicated. 1st what I did was get the angle where the rope attached to collar A and the rod, γ = cos-1 (40/50), γ=36.87 ; the to find x I just used tan36.87= 20/x  x = 20/tan36.87 so the result is x = 26.67in. I find that I over think a...

Thanks Doc Al I will look at it again when i get home from work.

I am just seeing if i am on the right path. A simple yes or no would be enough. Thank you

Equilibrium question with distance and weight Homework Statement Would someone be able to tell me if my attempt at this is correct. It seems too easy. If it is not could you help? Homework Equations Sum of the forces in the X direction Sum of the forces in the Y direction Mid...