Recent content by Faiien

Could you offer more assistance, I still don't really understand what to do.

Homework Statement Given the following reactions Fe2O3 + 3CO ---> 2Fe + 3CO2 DeltaH = -28.0kJ 3Fe + 4CO2 ---> 4CO + Fe3O4 DeltaH = 12.5kJ the enthalpy of the reactions of Fe2O3 with CO 3Fe2O3 + CO ---> CO2 +2Fe3O4 what is DeltaH for this equation? ________ kJ Homework Equations DeltaH =...

Homework Statement ( 1.3 g NaCl )+( 3.5 g AgNO3) ---> (xg AgCl) + (yg NaNO3) How many grams of each product result from the following reactions, and how many grams of which reactant is left over? Enter your answers numerically separated by commas. Express your answer using two...

Haha, ah I see now, thank you everyone.

I'm currently taking prerequisite classes at a community college (second semester) to enroll in a college which will grant me a PharmD but I'm not sure if I really want to become a pharmacist. The idea to be a pharmacist was actually my mothers and I had no better plans being a senior graduating...

So I'm taking chemistry again after a five hear hiatus from the topic and I would really appreciate an explanation on a certain formula. magnesium +oxygen forms magnesium oxide Mg+O2=MgO My question is, what happened to the 1 of the oxygen atoms? Shouldn't it be MgO2?

Homework Statement What is the density of lithium metal in g/cm^3 if a cylindrical wire with a diameter of 2.40mm and a length of 15.0cm has a mass of 0.3624g?Homework Equations D=m/VThe Attempt at a Solution The problem I'm having is I don't understand what the problem is asking. How do you...

Yes, I apologize, I did mean terms. Because the terms of an arithmetic sequence always vary by a constant x+a, x+2a. x+3a you can attain a, the constant, by subtracting two consecutive terms. (x+2a)-(x+a)=a or (x+3a)-(x+2a)=a

Because it's an arithmetic sequence, if you add a constant to one solution you can get the next solution.

Homework Statement Find x so that x+5, 3x+1, and 4x+1 are consecutive terms of an arithmetic sequence. Not really sure how to do the problem at all. Some assistance would be much appreciated.