Recent content by Faris Shajahan

While solving a Wheatstone bridge problem, we removing the bridging resistor and consider it as a parallel combination of series combination of two resistors. (I am sorry if I made it complicated) So what I mean is instead since no current flows through the bridge we can say the potential...

In a circuit if the potential difference between two points is zero, no current flows between the two points, right? Or am I wrong? I feel like I am wrong. If I am right, then in a Wheatstone bridge, no current passes through the bridge. Then instead of removing the bridge, why don't we connect...

Reason I asked this is because I feel like I used to do it another way before. It just bugs me. I can't do anything else basically. It is an issue I have, if I forget something I can't do anything for the next few days! So if anyone's got any other solution please post it if you don't mind. I...

I don't care. Just any other method other than the one I used. And I am kind of looking for a "not collision" method. eg. Body thrown with velocity ##v## from surface of earth. Find final height ##h##. (assume ##g## constant) Method 1: Newton's laws of motion and hence ##v = \sqrt{2gh}##...

Homework Statement Ball strikes inclined plane of infinite mass with velocity v vertically. Elastic collisions. Velocity and direction after collision? One way of solving is take components along and perpendicular to inclined plane and then solve easily. Is there any way to solve is using...

Yes, it will be different but still it would be impossible for us to calculate the value of ##X## as we don't have the value of ##r## given in the question. Instead if they say there is a rheostat in series with ε in order to maintain constant current in both the cases, then we can calculate...

I don't think that would solve the problem. Because even then, the current in both would be different. The first current would be ##I_1=\frac{E}{R+r}## and the second, ##I_2=\frac{E}{X+r}##... Hence there must be variable resistance whether or not there is internal resistance for the...

Wait a sec guys! I asked my Physics Sir today and he gave me what I would call a sensible answer! He said the circuit must be incomplete. This is because if we take the circuit shown in the figure, then as Aditya said, the balancing length would be the same (you see, the same emf is in parallel...

Oh right, I hadn't seen that!

Clearly possible. An example may be as shown, Let T be the tension in the string joining m and the closest pulley. Then in this figure we require a force>=T...where T=mg to lift the mass. But here, though T=mg, we only require force>=T/2 to lift the mass m!

I know what you mean and this method, I believe, uses constraints. It goes like... Let the length of the string between ##m_1## and the pulley at any time t be ##L##. And let the distance between the pulley and the table be ##y##. Let the horizontal distance between ##m_1## and the pulley be...

Could you please explain a little more...because I did not get what you exactly meant! Thanks though, it cleared "some" parts of my doubt...

Thanks! But what is wrong when we write ## v_2cos\theta=v_1 ##??

Homework Statement Homework Equations None... Newton's laws The Attempt at a Solution Not the attempt, the entire solution is: String length is constant...hence if on the right side of the pulley, the string goes up by x distance then on the right side also the string goes down by x...

Gosh, dude! I was fine but now you have confused me!