what is the pH of a 0.140M NaOCN solution? ka HOCN=3.5x10^-4
(rule of 100 can simplify 0.140-x to 0.140)
i know that ka=HOCN*OH^-/OCN^-=x^2/0.140
but i don't know the left hand side...i don't know what to do with HOCN=3.5x10^-4..
higher limit of 36
lower limit of 0 (36+3x)^1/2 dx
i thought of using subsititution?
The Attempt at a Solution
when x=0, u=36+3(0)=36
when x=36, u=36+3(36)=144
from lower limit of 36 to higher...
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