Differentiate, Evaluate Intergral

  • #1
Differentiate:

(6-xe^x)/(x+e^x)=...


Evaluate Intergral:

(2u^5-8u^3+5u^2)du, from lower limit -1 to higher limit 0.
(i got 10/3 for some reason...)

(u^7+6u^13)/u^9 du, from lower limit 1 to higher limit 2.
(n i got 47 for this..)

I tried these a few times but my answer is still not quite right, so im kinda stuck right now, can any1 help with the answers?
 
Last edited:

Answers and Replies

  • #2
rock.freak667
Homework Helper
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31
Differentiation one, just use the quotient rule and the product rule.

Did not check you intergals yet, but I think your 'dy's should be 'du's instead.
 
  • #3
sorry, i changed it to du.
For the differentiate, I did use the quotient and product rule, but somehow the answer is wrong.
 
  • #4
rock.freak667
Homework Helper
6,230
31
sorry, i changed it to du.
For the differentiate, I did use the quotient and product rule, but somehow the answer is wrong.
Could you post your attempt so we can see what, if anything you did wrong?
 
  • #5
[(-e^x-xe^x)(x+e^x)-(1+e^x)(6-xe^x)]/(x+e^x)^2
is this step right?
 
  • #6
171
0
Yes that is correct.
 
  • #7
oh, okay good.then i try to simply it i got [e^x^2+x^2e^x+6e^x+6]/(x+e^x)^2...which is not right...
 

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