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    How much work is done by friction during the car's slide down the hill?

    2) =>W = Delta Energy =>Delta Energy = kinetic friction * distance =>Delta Energy = 0.23 * 320 * 9.8 * [500/300] * 500 =>Delta Energy = 601067 J I reversed that and got this value. If it is not correct, then can you explain much clearer about the work energy theorem?
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    How much work is done by friction during the car's slide down the hill?

    I did it this way. 1) PE = mgh = 320 x 9.8 x 300 = 940800 J 2) By work energy theorem: =>W = Delta Energy =>Delta Energy = kinetic friction * distance =>Delta Energy = 0.23 * 320 * 9.8 * [300/500] * 500 =>Delta Energy = 216384 J I did it this way, but for question 2, should the...
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    How much work is done by friction during the car's slide down the hill?

    Homework Statement A 320 kg car slides from rest down a hillside that is 500 m long and 300 m high. The coefficient of kinetic friction between the car and the hill surface is 0.23. 1) If the gravitational potential energy PE of the car-Earth system is set to zero at the bottom of the...
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