Ok, so I add the two masses together (i assume) which gives me 172 kg all together. The horizontal force is still 613.4 N so i set up the equation F=ma 613.4N=(172kg)*a which then gives me an acceleration of 3.566 m/s^2 but that's incorrect.
Homework Statement
A 104.0-kg block is on a horizontal frictionless surface, on top of it is a second smaller block of 68.0-kg. A horizontal force F of 613.4 N is applied to the upper block which accelerates with 5.84 m/s2. 1. Find the coefficient of kinetic friction between the two blocks...
By the way, I appologize for putting this question in the wrong forum I saw "college physics" underneath the advanced physics part so I instantly just went that way without thinking twice
That's the problem though, they gave me nothing but the angle of the incline and the fact that the pig goes twice as slow with the friction. I am assuming that the equation for the frictionless pig is mgsin(theta) with m= mass, g=gravity. But i don't have mass so I have no idea what to do
I'm having a hard time figuring out the equation for this problem:
A pig slides down a 40.1 ° incline in twice the time it would take to slide down a frictionless 40.1 ° incline. What is the coefficient of kinetic friction between the pig and the incline?
Can somebody please help me I'm...