I was wondering if there was technology available that would allow for a rider to link with their bike and display a HUD (Heads Up Display) on the visor of the biker's helmet showing speed and other specs from the bike.
You have the right equation for work however since the elevator is moving at a constant velocity and its direction doesn't change, there actually is no acceleration present.
Something to consider is that because the elevator is moving in the y-direction, gravity also has an affect on the...
You'll need to know the equation for finding work done. If you draw out what is happening and then apply the forces of gravity, normal force, and force forward, you'll be able to determine the final velocity without much issue.
I'm noticing that if you have the equations for your various...
Do you know the equations that are needed to find both that static and kinetic coefficents? You have the initial maximum force and the sliding kinetic force as well as the of the object. These three pieces of information are all you will need to find the two coefficents.
For part (a), you'll need to know the equations to find the spring constant based off of the energy [E] that is exerted to move it the distance [x] it moves, which is also equal to its amplitude [A].
For (b), the force exerted can be found by using the spring constant value you found in (a)...
I think I have the right answers now but if you could check over my work and see, it would be appreciated.
Given:
\theta = 60^{o}
\Delta x = 850m
g = 9.8 m/s^{2}
v_{i} = 130 m/s
Find: \Delta Y_{f} and whether or not the projectile is rising or falling
Solution: Here's the RIGHT...
You have the right idea for finding the angular velocity. You have your equation and everything, simply move the variables around until you have an equation that will get you velocity.
v = \frac {2\pi r}{T}
v = \frac {18.85}{6.12}
v = 3.08 radians per second or rad/s
Unfortunately, I am...
To start with, this is very similar to a problem I had in my college physics course not too long ago. This time the given information was different so it took some tweaking to get the answers and I kept getting confused. However, when I reread the problem carefully, it made a whole world of...
ok, I'm just going to type in exactly what I wrote down on my scratch paper.
Given:
\Delta Y = 2 m
v_{i} = 0 m/s
95 kg/s = rate
g = -9.8 m/s^{2}
Find: v_{f}
Solution:
v_{fy}^2 - v_{iy}^2 = -2g\Delta Y
v_{fy}^2 = -2g\Delta Y + v_{iy}^2
v_{fy}^2 = -2(-9.8)(2) + (0)^2
v_{fy} =...
Now keep in mind that velocity and acceleration two different things. One measures the change in distance over a period of time and the other is the change in velocity over a period of time. Hence the units of measure being m/s and m/s^{2} respectively. So, to answer your question in a rather...
I can answer your random question (i'll also take a look at the actual problem to see if I can contribute any insight) but a_{y}=-g which means that acceleration taking place during a free fall is equal to negative gravity or -9.8 m/s^{2}
I know the 5 major ones.
a_{x} = constant
v_{fx} - v_{ix} = a_{x}\Delta t
\Delta x = (\frac{v_{ix} + v_{fx}}{2})\Delta t
\Delta x = v_{ix}\Delta t + \frac{1}{2}a_{x}\Delta t^{2}
v_{fx}^{2} - v_{ix}^{2} = 2a_{x}\Delta x
and then also how to convert them to work with a free fall problem...
[SOLVED] 2D Projectile Motion
So, this should be a relatively easy problem but I am thoroughly stumped and haven't a clue where to start.
A mortar used to launch fireworks fires a shell with an initial velocity v_{i}=130\mbox{m/s} at \theta_{i}=60^o above the horizontal. The shell explodes...
[SOLVED] Refresher on Derivatives
I feel rather dumb asking this but I could use a quick refresher on some parts of derivatives since for the past months I have been solely working on integrals and known cross sections so suddenly switching back has left my brain reeling.
The main question I...