Recent content by florianb

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    Quantum computers in the next 50 years?

    Agreed, cluster states are quite interesting. Among their advantages : Each computation starts from the same state, so there is only one state we need to be able to prepare The only thing that need to be done afterward is to measure qubits There are also drawbacks : The number...
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    Quantum computers in the next 50 years?

    Dear Lee, You will find a good, easy to read, review of how qubit can be implemented in Chuang and Nielsen's book : "Quantum Computation and Quantum Information", along with a lot of other interesting stuff. To be fair, answering such a question is pure speculation. There is definitely a...
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    Quantum computers in the next 50 years?

    Thanks for clarifying one of my questions. So this \alpha_3 constant is chosen so that Schrödinger's equation is reproduced for a particular wavefunction... It doesn't look to me as a proof that QM was derived from CM. It looks a lot more like what can be found in some textbooks, where...
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    Quantum computers in the next 50 years?

    There WILL be a quantum computer running in 49 years and 9 months. Why ? I have a bet running on this exact issue ;-)
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    Quantum computers in the next 50 years?

    You're right. I read the paper a little too fast. Although I still maintain my point that the form of equation (5) is odd for a classical derivation (I'm waiting for pointer to a proof to the contrary), the last part of my post was not correct, and I apologize for it : However, there are...
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    Quantum computers in the next 50 years?

    You're right in saying that non-local hidden variables theories can reproduce the results of Quantum Mechanics. See for example Bohmian mechanics : http://plato.stanford.edu/entries/qm-bohm/ However, I find that the article your refer to makes assumptions that are doubtful in the context of...
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    Quantum computers in the next 50 years?

    Sure, a computer can simulate quantum effects : You can solve Schrödinger's equation on a computer, this doesn't mean that this equation is classical. By putting a little more effort in your simulation, you will be able to violate Bell's Inequality too. There is no doubt about this. And...
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    Pauli Matrices and orthogonal projections

    Some hints Hey there ! Here are some hints on a was to do it : You will only use the fact that M^2 = M... 1) Compute M^2 : M^2 = \cfrac{1}{4}\left(\alpha I + \sum_i a_i \sigma_i \right)^2 = ... You will find a term like \sum_i \sum_j a_i a_j \sigma_i \sigma In order to...
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    Unraveling the Mystery of Interference in the Double Slit Experiment

    Electron diffraction LEED (Low energy electron diffraction) and RHEED (Reflection High Energy Electron Diffraction) are two experimental setup commonly used in material (surface) science. Both experiments result in diffraction patterns, where the wave-like nature of electrons is used to...
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    Time projection chamber and energy

    Thanks Thanks a lot Wolverine ! I came to the same conclusions, but I was still quite unsure about it (I'm not used to Bethe-Bloch, so this looked fuzzy to me). All the best !
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    Can Identical Quantum Particles Have Different Energies?

    Not quite... If you perform an experiment to find out the system energy, you're measuring the energy. Therefore, you're projecting the state into the the corresponding eigenspace. You will measure E1 with probability |a|^2 and E2 with prob. |b|^2 and the final state will be either |1> or...
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    Time projection chamber and energy

    Hi all ! I'm currently studying time projection chambers and I am wondering how the energy of the incident particle (the one that ionizes the gas in the drift chamber) is calculated from the measured signals. Does anyone have some hints for me ? Thanks a lot for your answers. Best regards
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    Is BB84 Quantum Cryptography Secure Against Eavesdropping?

    You're basically right Despite the fact that I'm not an expert, I think that you are basically correct. In fact, noise and eavesdropping both create bit flips in the final key that Alice and Bob have. If you try to correct errors induced by the noise of your quantum channel, you will also...
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