Recent content by fredgarvin22

i expected them to be equivelant because the (1) and (2) look equivelant to me. if you did this trick on just one of the identities alone, then the answer comes out the same. it seems to come up almost by accident because 2 terms from the two identities cancel each other out. and evidently this...

you are correct, the difference between the solutions is indeed b*ln(b). to me that means that in order for the constant of integration(which could any constant) to be equivilent in both equations, I need to either add or subtract this constant, which ever is appropriate, to the result. I'm...

that's very clever mathman - how did you come up with that?

hello everybody i hope i make this clear and to the point. there is an integral that is bothering me. i will express it as the combination of 2 integration formulas that you can look up, under logarithmic functions (http://en.wikipedia.org/wiki/List_of_integrals_of_logarithmic_functions) ...

hello could someone give me a pointer here. this integral ∫ln(x + c)dx my guess is, by integration by parts (ab)' = a'b + ab' ∫ba = ab - ∫b'a so here a = ln(c + x) b = c + x a' = 1/(c + x) b' = 1 ab = (c + x)*ln(c + x) and ∫b'a = ∫ ((c + x)/(hc + x)) dx = ∫dx = x...