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Ok great!...however I am having trouble isolating for r...On one side I have r/(1.20-r) and on the other side I have square root of 2.00/3.00 (due to squaring both sides to get rid of the power of 2. How do I isolate for this r?

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Hello comrades, Question A negative charge of 3.00 mC is 1.20m to the right of another negative charge of 2.00 mC. Calculate the point along the same line between the two charges where the net electric field will be zero. Formulas E=kq/r2 Attempt at Solving Well, I get as far as setting...

Homework Statement A 1300 kg car is traveling at 25 m/s as it passes the crest of a hill that has a radius of curvature of 120m. Determine the normal force acting on the car at the crest of the hill.Homework Equations The Attempt at a Solution I know that for horizontal surfaces the Normal...

I don't need to. All I need is mass of object 2.

mass of object 2 = 600 grams

I can't get it. I'v tried all sorts of ways but its that darn net force that I can't get! If I could just get that I'd have it.

Yes but I can't seem to get much from that...I have free body diagram of object 1 and 2 which is a block with Fg acting down and Ft acting up.

Ok so I have set up two equations for each mass. Fnet1=ma Fnet2=ma Fnet1=(.2kg)(4.90m/s squared) Fnet1=.98 N However I am stumped what to do with Fnet2. I go Fnet2=m(-4.90 m/s squared) then ma=m(-4.90m/s squared) but don't know what to do next.

Ok so would finding out the net force of object 1 help?

Lol ok thanks. I shall endeavour to solve this enigmatic question.

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Homework Statement Two masses are attached by a light string and looped over two frictionless pulleys. Object 1 (200g) accelerates upwards at a rate of 4.90 m/s squared. Determine mass of object 2. Homework EquationsThe Attempt at a Solution I tries doing this but don't think its right...