Recent content by Fresh4Christ

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    Solving large #s raised to a large # with the mod function

    Homework Statement Both of these questions are similar but the second is much larger so I thought I would post them both. Solve: 1) 252^(611) mod 1207 2) 8126^(3461) mod 8549 Homework Equations Well, the most difficult part is that the numbers are so large you cannot just...
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    Ultrasound Physics: Beam Uniformity Coefficient

    Thank you I appreciate it. I have looked at the Beam Uniformity Ratio (BUR) (SP/SA Factor) to see if that was related... I'm not seeing the connection. Any help is appreciated.
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    Ultrasound Physics: Beam Uniformity Coefficient

    Well, I have searched all over for information on it and cannot find anything. The only thing I have is that it is a unitless number with value of 1 or greater that describes spread of beam in space. I have googled it, looked it up in an old physics book... everything... just can't seem to...
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    Ultrasound Physics: Beam Uniformity Coefficient

    Pertaining to ultrasound physics, what is a "Beam Uniformity Coefficient"? How is it calculated? And why is it important? etc... I need to write couple page paper on it and I can't seem to find any information about it anywhere...Thanks.
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    Ultrasound Physics: What is the Beam Uniformity Coefficient?

    Pertaining to ultrasound physics, what is a "Beam Uniformity Coefficient"? How is it calculated? And why is it important? etc... I need to write couple page paper on it and I can't seem to find any information about it anywhere...Thanks.
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    0 = 3[cos(35)*cos(A) - sin(35)*sin(A)] - cos(A)

    Thank you soooo much!
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    Trig 0 = 3[cos(35)*cos(A) - sin(35)*sin(A)] - cos(A)

    i tried... this isn't a homework problem... its in the textbook. It jumps from that first step to the next one just saying "Then we can see:" ... and I can't see that
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    Trig 0 = 3[cos(35)*cos(A) - sin(35)*sin(A)] - cos(A)

    I have the problem: 0 = 3[cos(35)*cos(A) - sin(35)*sin(A)] - cos(A) where A is alpha...my unknown degree. somehow that turns into this: tan(A) = [cos(35) - 1/3] / sin(35) I am not drawing the connection or seeing how that is happening... Could you help? THANKS
  9. F

    0 = 3[cos(35)*cos(A) - sin(35)*sin(A)] - cos(A)

    I have the problem: 0 = 3[cos(35)*cos(A) - sin(35)*sin(A)] - cos(A) where A is alpha...my unknown degree. somehow that turns into this: tan(A) = [cos(35) - 1/3] / sin(35) I am not drawing the connection or seeing how that is happening... Could you help? THANKS
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