Recent content by FrogginTeach

This is my last week in Linear Algebra. I am working on our last homework assignment before the exam so I want to make sure I know what I am doing. In each part, make a conjecture about the eigenvectors and eigenvalues of the matrix A corresponding to the given transformation by considering...

Okay. I found the determinant of this 3x3 matrix: It is b1x + a2y + a1b1 - a2b1 - b2x - a1y I simplified it: b1x - b2x + a2y - a1y - a1b1 - a2b1 = 0 I'm not sure if this will help, but I did this next. b1x - b2x + a2y - a1y + C ; c = constant a2y-a1y = C - b1x + b2x y(a2 -...

I'm not sure if the question is asking what the graph of the determinant would look like or the matrix?

Sorry, I forgot about it being a 3x3 matrix.

The determinant is b1x - a2b1 a2b1 is a constant. So wait, I had that wrong. it is a straight line with a y-intercept which is some constant. How do you say that though?

Those 1's and 2's are supposed to be subscripts.

The question on my homework says: What can you say about the graph of the equation The following is in matrix form with determinant symbols around the matrix x y 1...

Okay. I decided to just choose systems to look at for a few of these problems. True 1. I found that Ax = 0 would also have infinitely many solutions. False 2. I found that Ax=0 would also be inconsistent. I'm not even sure where to begin with the others.

These homework questions are simply true or false questions requiring no work or explanation.

Ok. Here are my answers 1. True 2. True 3. False 4. False 5. True I'm not 100% confident in any of these answers.

I'm still a little confused.

I have taken Linear Algebra, but it has been a long time. I'm taking this course online and it is a lot harder to understand.

I am taking a Linear Algebra class to finish up my master's degree in math curriculum and instruction. I have been doing okay until these questions. I need some help. True/False 1. If Ax=b has infinitely many solutions, then so does Ax=0. 2. If Ax=b is inconsistent, then Ax=0 has only...