Recent content by Furby

Bungee Jump--Springs and Energy Homework Statement A person bungee jumps off a bridge. The person's mass is 90kg. The height of the bridge above the water is 80m. The bungee chord has a length of 25m. The bungee chord's spring constant is 30 N/m. What is the minimum distance the person...

Yup! =)

I have to apologize on my previous wording, the ball is accelerating vertically, but the velocity is just 0. If it wasn't accelerating, then in it would just float there in the air. That is the point where the velocity that is positive, and thus rising in position, changes to negative, and thus...

The mass of m2 doesn't alter due to the vertical force. Just simply the normal force, which combines with this new force to offset gravity and keep it from accelerating through the table. Friction, as you predicted, decreases due to this change, though. Otherwise, very nicely done.

Yes, I'm aware. That is what I'm stating. When you used that equation previously, you ended up finding meters. You seemed to be confused, and I was just telling you that that part of the rocket's motion took 20 seconds, as the problem strictly stated. Now find the other parts and add it to...

Speed=Distance/Time If your speed is 14km/h, and you travel a distance of 1 km, then the time is ? I'm sorry, I'm not sure I can walk you much farther without giving you the answer, but let me know if this doesn't help and I'll think of another way. =)

Vf=V0+a*t Vf2=V02+2*a*(y-y0) When you used the previous equation for part (1) for the first part of your rocket's motion (the accelerating upwards), you already knew the time (20s), so you didn't need to do any calculating. These are the kinematic equations for constant acceleration. You...

Alright, if the ball is not strictly vertical in motion, then your velocity for part a is nearly correct. You failed to account for the velocity's factor that assists in the horizontal motion of the ball, creating the parabolic trajectory. You found v0y, not the entire resulting velocity...

Yes, you're right. I tend to use velocity as synonymous with speed, which isn't correct. Often it will be negligible, though. Speed=Distance/Time Just plug and crank, now.

If your velocity is 14km/h, then if you drove a distance of 14km it would take you 1 hour, as I'm sure you're aware. Thus if you only drove a distance of 1 km . . . What is the formula for velocity? Think about the dimensions (units) of velocity.

As I understand it, in an introductory physics course, a ball thrown vertically is strictly vertical unless otherwise stated. Thus the trajectory would simply be a straight line, rather than a parabola with an x-component to the velocity. Is there a picture or any other reason to think...

Isn't 1m3=1000L? Correct me if I'm wrong, because there appears to be some dissonance, but I'm pretty assured I'm reading the problem as: A gas has a volume of 2m3 and a pressure of 700atm. What is the volume of the same gas at a new pressure of 1 atm? Temperature is constant. Thus...

Yeah, that was my assumption. = ), just wanted to be clear, especially that the upper block=m1. Try finding the force of friction applied to m1. Fk=uk*FN This is the force applied opposite to the direction of m1's motion.

It looks like you had friction in your equation (-fk) but did nothing with it. I think you calculated the velocity of the blocks without any friction. To be honest, I don't really understand the problem. What does it mean by 'between the upper block and the surface'?

I'm pretty sure you would use the ideal gas law. PV=nRT