Recent content by fuzzywolf

That does make sense. If you think of the relation space as a 5x5 matrix, then you can choose a diagonal element or any element in the strictly lower triangular part. Thank you!

I think you may have made a mistake in trying to skip a step on Kirchoff's rules. The expression you got for the left loop is only valid if R1 and R2 are in series. Are they? Go back to the basic rules: \SigmaI = 0 at a junction and \SigmaV = 0 around a loop. Those should give you three...

W = F * d is only a mathematical tool to calculate how much work is done. The applicable statement of physics is W = \DeltaE

I think you've got it essentially right. When calculating minimum escape energy, the idea is to include the kinetic energy due to tangential velocity and then apply force in the tangential direction. This takes a lot less energy than directing your force radially and moving out to infinity --...

I realized my mistake right after I posted. OP now shows {(1,1),(5,5),(1,5),(5,1)} Here's my new thought. If I let x be the subset of A that I am using for any given relation, then I have |x| identical mappings + some pairs of symmetric maps. If |x| = 1, then I just have 5 possible...

Homework Statement The set A has 5 elements. 1. How many relations exist on A? 2. How many of those relations are symmetric and reflexive? The Attempt at a Solution Some of the parts of this question are harder than others. 1. By simple counting, there are 2^(5^2) or 2^25 total relations...

If one particle starts at 0, and the other at r = 4, then one will accelerate in the positive r direction, and the other will accelerate in the negative x direction.

No, no, you're right in that. They won't meet in the middle, though, because they've been accelerated unequally. You want not xp = xe, but xp + xe = 4.

That is precisely correct. F = -kx assumes that one end of the spring is fixed, which is not true in this case. Try a special coordinate system where one direction is toward the center of the spring, and one direction is away from the center of the spring.

Ah, then if an < a(n+1), an/an+1 < 1 ... Have you tried showing that inequality?

Does the spring act only on m2?

If an >a(n+1), what does that imply about an / a(n+1)

Should they be equal? Does equal force imply equal acceleration in this case?

The range will be shortened compared to what? Be specific. Tell us what you think the Magnus effect means.

Why the kinetic energy of the electron decreases: KE = 1/2 mv^2 a = v^2/r, so v = (ar)^1/2, so: KE = 1/2 mar, where a is given by: F = ma = KQq/r^2 so a = KQq/(mr^2) so: KE = 1/2 Kqq/r Why the potential energy increases: At r = infinity, the proton and electron would feel no attraction. Bump...