The only problem I see is number 5 which can be argued as true. The question as you have it stated is "The current through a resistor is the same in circuits A and B." The key part of the question is "through a resistor." This may mean that only one resistor in B (2 ohms) is used, not the...
The only problem I see is number 5 which can be argued as true. The question as you have it stated is "The current through a resistor is the same in circuits A and B." The key part of the question is "through a resistor." This may mean that only one resistor in B (2 ohms) is used, not the...
The force of the rope and the work done by the rope are not pointing the same direction. According to the problem, the rope is inclined 28.5 degrees above the horizon and therefore has both an x and y component. The x component of the rope's force (cosine theta) is what points in the same...
To understand the first question, you need to understand the concepts of Newton's Third Law: Whenever one body exerts a force on a second body, the second body exerts an oppositely directed force of equal magnitude on the first body.
When the astronaut exerts a force on the ball at the wall...
Thanks everyone for the feedback.
The answer appears to be .14 m/s2. Looks like my initial confusion was coming from the fact that the man's weight wa attached to both ends of the rope!
Thanks again.
My apologies ConfusedStudent. Although the range formula is correct, my initial calculation may have been done in error. When double-checking today, I do get 23.8 m/s as V0.
Here is another way of solving the problem.
The horizontal displacement of the clubs is given by x=V0*t+at2/2 with...
Perhaps this will help, using a range formula.
We will assume no air resistance and be using g as the accleration due to gravity and sin Θ to represent the heigth of the clubs in the air (2Θ since the clubs must go up and down) we achieve the following variant of a kinematic...
Problem:
To hoist himself into a tree a 72 Kg man ties one end of a nylon rope of negligible weight around his waist and throws the other end over a branch of the tree. He then pulls downward on the free end of the rope with a force of 358N. Neglect any friction between the rope and the...
Basically, as the stone is thrown upwards, it is decelerating due to the acceleration due to gravity (g). Eventually, the velocity will reach zero at which time it begins the decent back to earth, again due to gravity. Therefore:
a) You are correct :smile: .Acceleration at the highest point...