Recent content by garyman

lol, finally I understand. I blame tiredness! Cheers for your help!

No. Has it got anything to do with partial fractions?

only the singularity at z=0 is enclosed, with the others being at +/- 3i. But i still can't see how to get it inot the correct form... If i could split up into multiple integrals, one with the singularity in the cauchy form and one without a singularity then i could make use of the fact that the...

z0 is the value of the singularity.

cauchys integral is : \intf(z)dz / [z-z0] = 2\pii f(z0) . I am trying to use this result to prove the statement.

Sorry, I don't understand. How does that get it in the form f(z)dz / [z-zo] ?

Sorry, the path is around the square with sides at x= +/- 2 and y= +/-2 .

Not sure, but if you split the fraction up into partial fractions its possible to get an integral of that form. Just not sure how to get the coefficents or indeed if its even the correct method.

Hi, I'm stuck on this question: Use the Cauchy's integral to show \ointcos(z) / [ z (z2 +9) ] dz = 2\pii/9 C is within the square defined by x= +/- 2 , y = +/- 2 I can't see how to get the denominator in the form (z-z0) to apply the theorem. Any help would be much appreciated! [

Hi, I'm slightly confused about how to prove that: \chi=\vartheta<M>/\varthetaH is equal to... \chi=(<M2>-<M>2 )/ T I've expressed <M> as \sumMsexp(-E/kBT) / \sumexp(-E/kBT) and know that E=-J\sumSiSj-H\sumSi But seem to get lost in the...

http://e.imagehost.org/0218/question.jpg I think I've managed to create the finite difference equation in part a), but I'm not sure how to turn this into a matrix equation. Any advice would be appreciated!

A Hohmann transfer orbit is used to send a spacecraft to neptune. However the positions of the other planets were not taken into consideration. The craft approaches Jupiter at an angle of 75 degrees to Jupiter's orbit. Calculate (a) the orbital velocity of Jupiter, (b) the probe's velocity...

Wasn't sure which section this should be in, so please move if inappropriate. If a plot between two variables theoretically should pass through the origin, should you force the linear regression through the origin. I seem to get a much better value for my gradient when forced through the origin...

\DeltaE=2\mu*B ,where E is doublet energy spacing, mu is the Bohr Magnetron and B is the magnetic field strength. I used excel to plot a linear-least squares regression line.

Its a plot of energy level spittings for transisitions for a cadmium dischrage lamp(J) against varying margnetic field(mT). The Graident of which is the Bohr Magnetron.