- #1

garyman

- 19

- 0

I'm stuck on this question:

Use the Cauchy's integral to show [tex]\oint[/tex]cos(z) / [ z (z

^{2}+9) ] dz = 2[tex]\pi[/tex]i/9

C is within the square defined by x= +/- 2 , y = +/- 2

I can't see how to get the denominator in the form (z-z0) to apply the theorem. Any help would be much appreciated!

[